Constant Acceleration Automobile

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Homework Help Overview

The problem involves an automobile accelerating from rest at a constant rate while a truck travels at a constant speed. The objective is to determine the distance at which the automobile overtakes the truck and its speed at that moment.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of the equations of motion for both the automobile and the truck, with one participant questioning the correctness of their calculations and another confirming the equation's validity.

Discussion Status

The discussion includes attempts to solve the problem using the quadratic equation, with one participant reporting a time calculation and subsequent speed calculation. There is an indication of progress, but no consensus on the correctness of the final results.

Contextual Notes

Participants are working within the constraints of a homework assignment, and there is a focus on verifying mathematical steps and assumptions related to the problem setup.

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[SOLVED] Constant Acceleration

Homework Statement



At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.1 m/s^2. At the same instant a truck is 10.2 m down the road and traveling with a constant speed of 8.5 m/s. (a) How far beyond the traffic signal will the automobile overtake the truck? (b) How fast will the automobile be traveling at that instant?

Homework Equations





The Attempt at a Solution



s(t) = 1/2 a * t^2 + v0 * t + s0
a = acceleration
v0 = initial speed
s0 = initial position


Being for the truck
a = 0 m/s^2
v0 = 8.5 m/s
s0 = 10.2 m
and being for the car
a = 2.1 m/s^2
v0 = 0 m/s
s0 = 0 m
the equation will be:
8.5 m/s * t + 10.2 m = (There is a 1/2 here right?) (1/2)2.1 m/s^2 * t^2

Solving this I get 9.156s which is apparently incorrect.
 
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I believe the equation you set up is correct. Can you show your math?
 
Well the math is kinda already there QQ I just plugged it into quadratic equation.
 
OK I got it!

s(9.16) = 1/2 (2.1) * (9.16)^2 = 88.1 meters

and after 9.16 seconds, it is traveling
v = at
v = 2.1(9.16) = 19.2 m/s
 
Awesome! Good job!
 

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