Constant acceleration of an antelope

[tAzneem]

An antelope moving with constant acceleration covers the distance 80.0m between
two points in time 6.70s. Its speed as it passes the second point is 14.6 m/s.
1) What is its speed at the first point?
2) What is the acceleration?

First I understand that when we have (constant acceleration) that means --> Vo=0m/s

*_______________* If that was the two points , so t1=0 , t2=6.70 and the all distance is 80
Vx=14.6
For 1 ) I though the answer will be zero OR can we do 80/6.70=11.9 , I really have an issue to know if the speed they are talking about is v=Δx/t or they are talking about S=D/t
2) α= Δv/Δt --> 14.6/6.70 = 2.2m/s^2

 

[Dick]

An antelope moving with constant acceleration covers the distance 80.0m between
two points in time 6.70s. Its speed as it passes the second point is 14.6 m/s.
1) What is its speed at the first point?
2) What is the acceleration?

First I understand that when we have (constant acceleration) that means --> Vo=0m/s

*_______________* If that was the two points , so t1=0 , t2=6.70 and the all distance is 80
Vx=14.6
For 1 ) I though the answer will be zero OR can we do 80/6.70=11.9 , I really have an issue to know if the speed they are talking about is v=Δx/t or they are talking about S=D/t
2) α= Δv/Δt --> 14.6/6.70 = 2.2m/s^2

Homework Statement

Homework Equations

The Attempt at a Solution

Constant acceleration doesn't mean v0=0m/s. It just means the acceleration 'a' is constant. What are formulas for displacement and velocity assuming initial velocity v0 and constant acceleration a? Something like x=v0*t is only true if there is no acceleration.

 

[tAzneem]

Sorry , but I didn't get it , ok constant a , doesn't mean Vo=0
Can you explain the Q. more for me

 

[Ray Vickson]

Sorry , but I didn't get it , ok constant a , doesn't mean Vo=0
Can you explain the Q. more for me

You can fire a toy rocket forward with constant acceleration, either starting from rest or starting from a moving car. The acceleration is the same, but the two situations give different velocities; they differ by the velocity the car had at the launch point. It's not rocket science!

 

[Dick]

Sorry , but I didn't get it , ok constant a , doesn't mean Vo=0
Can you explain the Q. more for me

If there is no acceleration you can write the displacement as x(t)=x0+v0*t, where x0 is the initial position and v0 is the initial velocity. There is a similar expression for the case of constant acceleration. You must have seen it before. Try to find it.

 

[tAzneem]

Ok thank you both