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Bell writes: "Then, as reckoned by an observer in A - the rest observer at the starting position -, they will have at every moment the same velocity, and so remain displaced one from the other by a fixed distance". This is a constant acceleration motion description.PeterDonis said:I think that depends on what Bell meant by "identical acceleration programmes". I think he meant "same F/M ratio". In other words, he was specifying what the spaceships' engines were programmed to do: put out the same constant F/M.
Wikipedia comments: "Bell's spaceship paradox is not about preserving the rest length between objects (as in Born rigidity), but about preserving the distance in an inertial frame relative to which the objects are in motion...".
Bell scenario is in the Chapter 9 of the book "Speakable and unspeakable in Quantum Mechanics". The title of the chapter is "How to teach Special Relativity". So, is an example chosen to teach SR. As such, is not a very precise description, and needed to put some drama in the plot.
I think that some pages after, Bell's says something like "actually, the thread will pull the spaceships and break if it can't change the acceleration of the heavy masses of the spaceships" (I don't have now the exact quote, but I remember more or less). All very imprecise.
But, of course, what seems to happen is that there's really no need for the string to be "weak", because the relativistic acceleration due to the time dilation in accelerated motion is so tiny, that at 1g, a spaceship of 109 Kg, would not be able to break a 0,02 N ultimate tensile strength thread, and so the students would probably say: bah, and what's the point then? It introduced some dramatic effects for the string.