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## Homework Statement

Dario, a prep cook at an Italian restaurant, spins a salad spinner 20.0 times in 5.00 seconds and then stops spinning it. The salad spinner rotates 6.00 more times before it comes to rest. Assume that the spinner slows down with constant angular acceleration.

a) Find the angular distance the salad spinner travels as it comes to rest

b) What is the angular acceleration of the salad spinner as it slows down?

## Homework Equations

constant rotational equations

## The Attempt at a Solution

a) ok, i found initially when the spinner is spinning 20 times in 5seconds to have a angular velocity of 1440 degrees. For the second part when it spins 6 more times, i calculated: [tex]\frac{6 * 360}{5}[/tex]

so angular distance is 1440-432 = 1008 degrees

b) To find angular acceleration i used the formula : [tex]\omega final^2 = \omega initial^2 + 2\alpha\theta [/tex]

[tex]432^2 = 1440^2 + 2\alpha * 1008[/tex]

[tex]\alpha = \frac{186624 - 2073600}{2016}[/tex]

[tex]\alpha = 936 rad/s^2[/tex]

Can someone please check if this is correct.

P.S

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