Container with two gas compartments separated by piston

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SUMMARY

The discussion revolves around a problem from Reif's "Fundamentals of Statistical Mechanics," specifically problem 5.4, involving a cylindrical container with two gas compartments separated by a piston. The left compartment contains 1 mole of helium gas at 5 atm, while the right compartment contains argon gas at 1 atm. Upon unclamping the piston, the system reaches a new equilibrium, prompting questions about the increase in water temperature, the final position of the piston, and the total entropy change of the system. The ideal gas behavior and the principles of thermodynamics are central to solving this problem.

PREREQUISITES
  • Understanding of ideal gas laws, specifically PV = nRT
  • Familiarity with thermodynamic principles, including entropy and energy equations
  • Knowledge of heat transfer concepts in thermodynamic systems
  • Basic skills in solving equilibrium problems in statistical mechanics
NEXT STEPS
  • Study the implications of the first law of thermodynamics in closed systems
  • Learn about entropy calculations in thermodynamic processes
  • Explore the concept of thermal equilibrium and its applications in gas mixtures
  • Investigate the behavior of ideal gases under varying pressure and temperature conditions
USEFUL FOR

This discussion is beneficial for students and educators in physics, particularly those studying thermodynamics and statistical mechanics, as well as anyone interested in understanding gas behavior in confined systems.

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Homework Statement



This is Reif, Fundamentals of Statistical Mechanics, problem 5.4

A cylindrical container 80 cm long is separated into two compartments by a thin piston, originally clamped in position 30 cm from the left end. The left compartment is filled with 1 mole of helium gas at a pressure of 5 atm; the right compartment is filled with argon gas at 1 atmosphere pressure.

These gases may be considered ideal. The cylinder is submerged in 1 liter of water, and the entire system is initially at the uniform temperature 25 deg C. The heat capacities of the cylinder and piston may be neglected. When the piston is unclamped, a new equilibrium situation is ultimately reached with the piston in a new position.

a) What is the increase in temperature of the water?
b) How far from the left end of the cylinder will the piston come to rest?
c) What is the increase of total entropy of the system?

Homework Equations



PV = nRT
dE = TdS - PdV

The Attempt at a Solution



This is a confusing problem because of all the possible ways heat can flow. The fact that part a) asks for the temperature increase of the water means that heat can flow across the cylinder boundary. It also says to ignore the specific heat of the cylinder and piston, which suggests that heat can also flow across the piston.

What I'm pretty sure of is that the piston will move to the right until the pressures of the two sides are equal (at which point the piston will stop due to the balance of force).

Now if no heat flowed in this problem, this would leave the left side at colder than 25 C (since it was the side that pushed the piston and did work) and the right side at hotter than 25 C (since the piston did work on it).

Now if we look at the temperatures, we have:
water: 25 C
left side: <25 C
right side: >25 C

this means that heat will flow in several different ways:
water --> left
right --> left
right --> water

With all these different heat flows, I have no idea where to begin in this problem.
 
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I don't think there is a need to worry exactly how the heat flows, the important thing is that the final temperature and pressure will be the same in both parts of the cylinder.
 

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