I Conventional description of the matter wave

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The discussion focuses on finding a state function solution for a quantum wave function that remains invariant under arbitrary displacements in space and time. A proposed solution is sin(kx-wt) + acos(kx-wt), where it is determined that a must equal ±i. The conclusion is that the convention requires γγ=i to ensure the wave function corresponds to positive energy states. If γ were -i, it would lead to negative energy states, contradicting the principles of quantum mechanics. Thus, the positive coefficient of the cosine term is essential for maintaining the correct energy sign in the wave function.
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Conventional description of the matter wave
I have been working on a relatively simple problem. Just take a quantum wave function for which a physical requirement is that an arbitrary displacement of x or an arbitrary shift of t should not alter the character of the wave, and I want to find the state function solution. A possible guess that works is sin(kx-wt)+acos(kx-wt). I found out that a=±i, and then I have to say which one corresponds to the convention. I said that it must be that γγ=i, because if it was -i, then the time derivative of the state function would have been negative, and using Schrodinger equation that would imply negative energy states. Am I right?
 
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Yes, you are correct. The convention that is usually used is that the wave function should have a positive energy, and so the time derivative of the wave function should be positive. Therefore, the coefficient of the cosine term must be +i in order for the wave function to satisfy this requirement.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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