Convergence in mean square (or L^2) sense

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SUMMARY

The discussion focuses on the convergence of the series defined by fn(x) = [n/(1+n²x²)] - (n-1)/[1+(n-1)²x²] in the mean square (L²) sense. The series does not converge to zero as N approaches infinity, as demonstrated by the integral NL∫ (N/(1+y²)²) dy diverging to +∞. The change of variable y=Nx is crucial for simplifying the integral and analyzing the behavior of the series as N increases. This transformation allows for a clearer understanding of the limits and the integrand's growth.

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kingwinner
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Convergence in "mean square" (or L^2) sense

Homework Statement


This is an example from a textbook (with solutions) in which I am feeling confused.
Let fn(x) = [n/(1+n2x2)] - (n-1)/[1+(n-1)2x2] in the interval 0<x<L. This series telescopes so that
N
∑ fn(x) = N/(1+N2x2)
n=1

L
∫ [∑ fn(x)]2 dx =
0
L
∫ N2/(1+N2x2)2 dx =
0
NL
∫ N/(1+y2)2 dy (let y=Nx)
0
This last line -> +∞ as N->∞
Since it does not converge to 0, the series does NOT converge in the mean-square (or L2) sense to f(x)=0.

2. Homework Equations /concepts
Convergence in mean square/L2 sense

The Attempt at a Solution


N/A

(i) Now I don't understand why we have to use the change of variable y=Nx. What is the point of doing this?


(ii) Also, WHY as N->∞,
NL
∫ N/(1+y2)2 dy -> +∞ ?
0

Can someone please explain?
Thank you!
 
Physics news on Phys.org


Why is it a good idea to bring N into the limits of integration? After the change of variable, N appears both in the upper limit of integration AND in the integrand...
 

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