gomes. Messages 58 Reaction score 0 Thread starter Jan 19, 2011 #1 Stuck on part iii, I am not sure what I've done wrong as my answer seems correct! any help wil be appreciated. And err, I can't seem to do part (iv) and (v), any help will be appreciated, thanks! Attachments analysis.jpg 24.1 KB · Views: 379
Stuck on part iii, I am not sure what I've done wrong as my answer seems correct! any help wil be appreciated. And err, I can't seem to do part (iv) and (v), any help will be appreciated, thanks!
micromass Staff Emeritus Science Advisor Homework Helper Insights Author Messages 22,170 Reaction score 3,335 Jan 19, 2011 #2 It seems that you want to show [tex]\frac{1-\frac{1}{2r}}{1+\frac{1}{r}}\leq \frac{1}{(1+\frac{1}{r})^{3/2}}[/tex] This is equivalent to [tex](1-\frac{1}{2r})(1+\frac{1}{r})^{3/2}\leq 1+\frac{1}{r}[/tex] Try to work this out. Things you could do to simplify this is squaring both terms and multiplying both sides by a suitable power of r.
It seems that you want to show [tex]\frac{1-\frac{1}{2r}}{1+\frac{1}{r}}\leq \frac{1}{(1+\frac{1}{r})^{3/2}}[/tex] This is equivalent to [tex](1-\frac{1}{2r})(1+\frac{1}{r})^{3/2}\leq 1+\frac{1}{r}[/tex] Try to work this out. Things you could do to simplify this is squaring both terms and multiplying both sides by a suitable power of r.