MHB Convert 243 to Base 3 using Digit 5

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To convert the decimal number 243 to base 3 using the digit 5, the calculation for the base (n) is determined by the formula n = d % 6 + 2, resulting in n = 3. The conversion of 243 to base 3 yields the representation {100000}_3. The discussion clarifies that the modulus operator (%) is used to find the remainder in this context. The calculations and results are confirmed to be correct. This conversion process illustrates the application of mathematical principles in base conversion.
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Guys Can you help me out, i don't know if I've done this right.

Question:
243 is a decimal number. You must convert it to base n, where n will be computed using the
digit (d) 5.
For example if your digit (d) was "7" , then n is
calculated as: n = d % 6 +2(where d=7)=7%6 + 2 = 3My Working:

n = d % 6 + 2 (where d=5) = 5%6 + 2 = 3
243 to the base of 3 = {100000}_{3}
 
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HELPMEHELPME said:
n = d % 6 + 2 (where d=5) = 5%6 + 2 = 3
Sometimes, e.g., in the C programming language, % denotes taking the remainder.
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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