Converting 243 to Base 3 Using the Digit 5 | Number Systems Homework

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Discussion Overview

The discussion revolves around converting the decimal number 243 to a base determined by a formula involving the digit 5. Participants are trying to understand the formula for calculating the base (n) and whether the conversion to base 3 is correct.

Discussion Character

  • Homework-related
  • Debate/contested
  • Exploratory

Main Points Raised

  • One participant states that using the formula n = d % 6 + 2 with d=5 results in n=3, leading to the conversion of 243 to base 3 as 1000003.
  • Another participant questions whether d is given or derived, expressing confusion about the problem statement and the example provided.
  • Some participants express uncertainty about the correctness of the calculation for n, with one seeking confirmation on whether their calculation is accurate.
  • A later reply suggests that the problem statement is odd, noting inconsistencies in how n is defined and questioning the clarity of the formula.
  • There is a discussion about the interpretation of the symbols used in the formula, particularly the modulo operator and its implications for the calculation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the calculation for n or the clarity of the problem statement. Multiple competing views and uncertainties remain regarding the interpretation of the formula and the conversion process.

Contextual Notes

There are limitations in the problem statement's clarity, particularly regarding the definitions and roles of the variables involved. The exact meaning of the symbols used in the formula is also unresolved.

gEOdude
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Homework Statement


243 is a decimal number. You must convert it to base n, where n will be computed using the
digit (d) 5.
For example if your digit (d) was "7" , then n is
calculated as :n = d % 6 + 2 (where d = 7) = 7%6 + 2 = 3

Homework Equations


None.

The Attempt at a Solution



n = d % 6 + 2 (where d=5) = 5%6 + 2 = 3

243 to the base of 3 =
1000003
 
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d is given? Or does it come from somewhere else?
You used the example of d=7, I'm not sure if that was the idea of the homework problem.
 
mfb said:
d is given? Or does it come from somewhere else?
You used the example of d=7, I'm not sure if that was the idea of the homework problem.
d is given as 5. But when i plug it into the formula to calculate n i keep getting 3. I am probably wrong because I am not calculating it right. I am not having any difficulty with anything else, just that bit. So if i can get some assistance on calculating n with d=5 then I will be fine. Thanks.
 
gEOdude said:
d is given as 5. But when i plug it into the formula to calculate n i keep getting 3. I am probably wrong because I am not calculating it right. I am not having any difficulty with anything else, just that bit. So if i can get some assistance on calculating n with d=5 then I will be fine. Thanks.

All I know is 24310 = 35

Using place-value, 1000003 = 1×35 + 0×34 + 0×33 + 0×32 + 0×31 + 0×30
 
DId i calculate n right? CAN SOMEONE TELL ME IF I CALCULATED N RIGHT OR IF IM DOING SOMETHING WRONG. PLEASE!
 
gEOdude said:
DId i calculate n right?
Beats me. I don't understand the question or the formula you posted. Can you provide a reference or other information?
 
gEOdude said:

Homework Statement


243 is a decimal number. You must convert it to base n, where n will be computed using the
digit (d) 5.
For example if your digit (d) was "7" , then n is
calculated as :n = d % 6 + 2 (where d = 7) = 7%6 + 2 = 3
If this is the full and exact problem statement, it is very odd.

If you plug d=5 into the formula then n won't be 3.
 
This is indeed very strange.
You seem to have two distinct questions:
- convert a number into a different base, base n. This is very simple, so I don't think you have a problem here.
- find out what number n is. That is difficult because no one has defined n for you, just given an example using numbers conjured out of thin air!

The statement of the problem is odd to me: if n is to be computed from 5, why say (d)? And in your example, it is computed from 7, 6 and 2. If this really means (d), 6 and 2, why is 7 given a name (d) and 6 and 2 are not given names?

DId i calculate n right? CAN SOMEONE TELL ME IF I CALCULATED N RIGHT OR IF IM DOING SOMETHING WRONG. PLEASE!

So I can't tell you if you used the right formula. Using the formula you gave as an example,
:n = d % 6 + 2
and assuming % means modulo and : means nothing, then
5 % 6 + 2 <> 3 so your calculation is in error.
if % means integer division and : means nothing, then
5 % 6 + 2 <> 3 so your calculation is in error.

I can't tell which of these is the correct error, since 7 mod 6 = 1 and int( 7/6) =1 so your % could be either, but this is where your calculation seems to err, unless you can suggest another meaning for the % symbol or the : symbol.
 
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