Converting 1,602 ×10^−19 C to SI Unit Prefixes

[at94official]

Just simple questions and I need clarifications why is that your answer please.
1,602 ×10^−19 C write to SI Unit Prefixes

 

[spaghetti3451]

Let me try and see if I understand your query - you say you have a simple question, but that you would require a detailed response, rather than a short answer. Am I right?

I'm not really sure what you mean when say 'SI unit prefixes' - perhaps you want to rewrite $1.602 \times 10^{-19}\ \text{C}$ as $16.02\ \text{atto C}$, or perhaps as $1\ \text{eV}$ ??

 

[at94official]

Let me try and see if I understand your query - you say you have a simple question, but that you would require a detailed response, rather than a short answer. Am I right?

I'm not really sure what you mean when say 'SI unit prefixes' - perhaps you want to rewrite $1.602 \times 10^{-19} C$ as $16.02 \text{atto} C$, or perhaps as $1 eV$ ??

Im sorry, I mean I just want a simple answer and requesting for some explanations why.
and to your answer, if we will base it on Unit Prefixes. Atto is -18 not -19 , can you explain this? sorry having trouble understanding this part of SI Units.Prefix Symbol Exponent Prefix Symbol Exponentyotta Y 1024 yocto y 10−24

zetta Z 1021 zepto z 10−21

exa E 1018 atto a 10−18

peta P 1015 femto f 10−15

tera T 1012 pico p 10−12

giga G 109 nano n 10−9

mega M 106 micro μ 10−6

kilo k 103 milli m 10−3

hecto h 102 centi c 10−2

deca da 101 deci d 10−1

 

[spaghetti3451]

Well, $1.602 \times 10^{-19}\ \text{C} = 1.602 \times 10^{-1} \times 10^{-18}\ \text{C} = 1.602 \times 10^{-1}\ \text{atto C} = 0.1602\ \text{atto C}$.

So, I was wrong the first time round!

 

[at94official]

Oh okay, so if that the case you just have to multiply the excess ?

 

[spaghetti3451]

Exactly!

Multiply the excess $10^{-1}$ with $1.602$.