# Converting Acceleration to Velocity

• Thrawn

## Homework Statement

Is velocity equivalent to the square root of accelleration?

V = d/t

## The Attempt at a Solution

A = accelleration, expressed in meters per second squared

V = distance (m) divided by time (s)

So V = sqrt A ?

In the context of the question: How long does it take an object with a mass of 100g (.1kg) mass to travel 10 cm (.1m), with a force (assumed to be constant) of 0.0000000132944 N.

Last edited:
Is velocity equivalent to the square root of accelleration?
Uh... no.

A = accelleration, expressed in meters per second squared

V = distance (m) divided by time (s)

So V = sqrt A ?
If velocity were the square root of acceleration, it would have units of square root of distance divided by time.

In the context of the question: How long does it take an object with a mass of 100g (.1kg) mass to travel 10 cm (.1m), with a force (assumed to be constant) of 0.0000000132944 N.
Time for you to review basic kinematics. Find an expression that relates distance with time for a given acceleration.

Precisely, acceleration is the derivitive of velocity, expressed in m/s per second. Its the rate of change of velocity, or V/t. That means V = At

Your question relates distance (not velocity) to acceleration, in which case you need to find the constant acceleration and then plug it into the kinematic equation D = vo + .5at^2

If possible, could someone direct me to a website which provides an introduction (prefferably oriented towards beginners with very little prior knowledge of the subject or complementary subjects) to the kinematics involved in this equation?

Don't you have a textbook that defines acceleration?

This site isn't bad: http://www.physicsclassroom.com/Class/1DKin/U1L6a.html" [Broken]

And check out our own tutorial section: https://www.physicsforums.com/showthread.php?t=95426"

Last edited by a moderator:
Don't you have a textbook that defines acceleration?

I wish I had a textbook for this... but alas, it is not covered in the Ontario Grade 8 curriculum, as such a physics textbook would be rather unneccessary, as it is not taught...

This site isn't bad: http://www.physicsclassroom.com/Class/1DKin/U1L6a.html" [Broken]

And check out our own tutorial section: https://www.physicsforums.com/showthread.php?t=95426"

Thank you.

Last edited by a moderator:
Having found the appropriate kinematic equation, I have calculated the following:

d = Vi*t + 0.5*a*t^2

= 0m/s*t + 0.5*a*t^2

= a*t^2/2

2d= a*t^2

2(0.1m)/a = t^2

0.2/0.000000132944m/s^2 = t^2

sqrt 1 504 392.827055000617 = t

t = 1 226.5369244 s

Is the value for t, one thousand two hundred twenty - six seconds correct, and was the equation used correctly?

That looks fine. A few comments:

Express numbers such as the force using exponential notation (like 1.32944 × 10^-8 N); they are much easier to read that way instead of a string of zeroes.

Take care with significant figures. It looks like your values for mass and distance only have one significant figure--yet your answer has around 20. Not very realistic! (Just because the calculator carries all those digits doesn't mean you should keep them in your answer.)