Converting Celsius to Kelvin Easy but slightly confusing

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SUMMARY

The discussion focuses on converting Celsius to Kelvin while performing temperature subtraction. The correct method to find the difference between two Celsius temperatures, 34.73C and 63C, is to first subtract the Celsius values directly, yielding -28.27C, and then convert this difference to Kelvin by adding 273, resulting in 244.73K. The alternative method of converting both temperatures to Kelvin before subtraction is incorrect as it cancels out the Kelvin units. The key takeaway is that the difference in temperature remains the same in both Celsius and Kelvin scales.

PREREQUISITES
  • Understanding of temperature scales (Celsius and Kelvin)
  • Basic arithmetic operations (addition and subtraction)
  • Knowledge of temperature conversion formulas
  • Familiarity with calorimetry concepts
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  • Study the principles of temperature conversion between Celsius and Kelvin
  • Learn about the significance of absolute zero in temperature scales
  • Explore the applications of calorimetry in thermodynamics
  • Investigate common mistakes in temperature calculations and how to avoid them
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Homework Statement



I'm doing calorimetry, and I have 34.73C and 63C. I need to subtract 63 from 34.73, and get the answer in Kelvin.

Homework Equations


The Attempt at a Solution



I know you add 273 to Celsius values to get Kelvin, but I am not sure which of these methods is correct:

1. (34.73C+273) - (63C+273) = -28.27K
2. 34.73C-63C = -28.27C. Then, -28.27C + 273 = 244.73K

Which one is the correct method? The first one seems unlikely just because the Kelvin's are essentially canceled out in the equation..
 
Last edited:
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The first one. You are subtracting one temperature from another so the "base"- that is what temperature corresponds to 0- is irrelevant. You could as easily have just said that 34.73- 63= -28.27 degrees. Since 1 degree celsius is the same "size" as 1 degree Kelvin, the difference is the same in both systems.
 
Ah I just realized that I was calculating the DECREASE in temperature of hot water, so a negative decrease is a positive value. Thanks!
 
Last edited:

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