Convex Subsets of Topological Vector Spaces

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SUMMARY

The proof presented for the theorem stating that if C is a convex subset of a topological vector space X containing the origin, then the set tC is a subset of C for each 0 ≤ t ≤ 1, is correct. The proof relies on the definition of convexity, demonstrating that for any x in C, the expression t*x + (1-t)*0 remains in C. Additionally, it is established that the theorem holds true for any vector space over the real or complex numbers, not just topological vector spaces. This highlights the broader applicability of the theorem beyond its initial context.

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Edwin
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I had a quick question:

Is the following proof of the theorem below correct?


Theorem: If C is a convex subset of a Topological vector space X, and the origin 0 in X is contained in C, then the set tC is a subset of C for each 0<=t<=1.

Proof: Since C is convex, then

t*x + (1-t)*y is contained in C, for every x,y in C, and for 0<=t<=1.

Since y = 0 is contained in C, then in particular,

t*x = t*x + (1-t)*0 = t*x + (1-t)*y is contained in C, for every x in C, and for 0<=t<=1.

Hence tC is a subset of C for 0<=t<=1. This completes the proof.



Is the above proof correct? Or, did I make a mistake in the proof?
 
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Yes, the proof is correct. As a side remark, note that you did not need the vector space to be equipped with a topology. Thus the theorem is true (with the same proof) for any vector space over the real or complex numbers.
 
Thank you for the information! I had not noticed that.

So then the essential information in the proof are the vector space axioms (where the scalar field is either the real or complex numbers), and the definition of a convex set. The case of a Topological vector space is then just a special case of the more general theorem applied to an arbitrary vector space. Interesting.
 

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