Convexity of a function I don't understand

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The function discussed is defined as f(x) = maxi(xi) - mini(xi) over the domain R. The user concludes that f(x) equals 0, as the maximum and minimum of x in R are both x itself. The function is determined to be convex since for any θ ≥ 0, the condition f(θ.x + (1-θ).y) = 0 holds true. The user seeks clarification on whether the argument of f is a vector, with x_i representing its components.

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Hi,

I am starting to learn real math I would say for first time in life. I have come across this function:

Code:
f(x) = max[SUB]i[/SUB](x[SUB]i[/SUB]) - min[SUB]i[/SUB](x[SUB]i[/SUB])

The domain is R.

Does the above function mean f(x) = 0 since for for x in R max and min of x would be x itself.

Hence it is convex as for any θ ≥ 0 we can write:
Code:
θ.x + (1-θ).y = 0 ≤ f(θ.x + (1-θ).y)
f(θ.x + (1-θ).y) = 0

In above both x and y would be any R.

Thanks for helping me learn.
 
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Is the argument of [itex]f[/itex] perhaps a vector and the [itex]x_i[/itex] the components thereof? I am sure they are not meant to be the same.
 

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