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Convolution of a function with itself

  1. Apr 16, 2008 #1
    given a function f(t) could we define the operation

    [tex] f*f*f*f*f*f*f*f**f*f*f*f*..........*f [/tex] n times ?

    here the operation '*' means convolution of a function if n=2 i know the expression

    [tex] (f*f)= \int_{0}^{x}dt f(t)f(t-x) [/tex]

    but i would like to see if this can be applied to arbitrary order , thanks.
  2. jcsd
  3. Apr 16, 2008 #2


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    There is nothing in mathematics to prevent you from doing it.
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