- #1

Sakha

- 297

- 0

## Homework Statement

A thief steals a car in front of two cops, A and B.

The thief's initial velocity is 25m/s, cop A starts his car with 3m/s

^{2}, and cop B starts 10 seconds after cop A, but with 5m/s

^{2}. After 200m from his initial point, the thief notices the cops and start accelerating at 1m/s

^{2}

Which cop catches the thief? At what time does he catch it?

## Homework Equations

d= V

_{o}t+1/2at

^{2}

I think that's the only required formula

## The Attempt at a Solution

I tried to set an equality between the distance of the thief and the distance of cop A, but I get stuck in the math to solve for t.

(25m/s)(t)+(1/2)(m/s

^{2})+200m=(1.5m/s

^{2})(t+8)

^{2}

t is the time since the thief started accelerating, and that happens 8s after A started.

after doing math here I get completely stuck with the algebra.