Correcting My Answer: Ensuring Accuracy and Improving Learning

  • Thread starter Thread starter r-soy
  • Start date Start date
  • Tags Tags
    Important
Click For Summary

Homework Help Overview

The discussion revolves around the calculation of the ninth root of -512 and its implications in a sequence problem involving the fifth term of a geometric series. Participants are examining the correctness of substitutions and calculations related to the formula for the nth term of a geometric series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the validity of the ninth root calculation and its application in the context of the geometric series formula. There is a focus on identifying mistakes in substitutions and the interpretation of terms.

Discussion Status

The discussion is active, with participants providing feedback on errors and suggesting areas for revision. There is no explicit consensus, but several participants are guiding the original poster to reconsider their calculations and assumptions.

Contextual Notes

Participants note discrepancies in the original poster's calculations, particularly regarding the values used in the formula and the interpretation of the terms. The original poster's understanding of the problem setup is being questioned, especially concerning the correct identification of terms and calculations.

r-soy
Messages
170
Reaction score
1
Hi

I want check my answer and If there any mistake please correct it to me[/b]
 

Attachments

  • ticc.JPG
    ticc.JPG
    25.6 KB · Views: 423
Physics news on Phys.org
The ninth root of -512 is not equal to -56.
 
what is the mistake ?
 
-512 divided by 9 [itex]\approx[/itex] -56 (but not exactly)
But the ninth root is not division.

Anyway, following on from that mistake, when you used the formula:

[tex]\frac{a\left(1-r^n\right)}{1-r}[/tex]

You substituted incorrectly. a=1/4, r=-56 (your mistake), n=5 (since it asks for the 5th term)
This is what you had:
[tex]\frac{\frac{1}{4}\left(1-(-56)^9\right)}{1-(-9)}[/tex]

This is what you should have:
[tex]\frac{\frac{1}{4}\left(1-(-56)^5\right)}{1-(-56)}[/tex]

But anyway, following on from that mistake also, whatever happened to the [itex]1-r^n[/itex] part?

[itex]1-(-56)^9[/itex] all of a sudden became something like 5x4 from the looks of it, but since you end up with the answer of -5.7 from there, it means that part must've been equal to 182.4, but it doesn't seem like it is.

Honestly, you need to go back and revise your algebra. You will struggle to solve all these harder questions if you don't have a firm foundation with algebra.
 
Oh and you wrote that the right-hand column is T10. The question says to find the 5th term (T5) and already gives you [itex]T_{10}=-128[/itex].
 
You're given that a = -1/4 and T10 = -128, and you need to find the common ratio r.

T10 = ar9
==> -128 = (-1/4)r9
==> -512 = r9
==> [tex]r = \sqrt[9]{-512}[/tex]
As I said in my first post, the 9th root of -512 is not -56. If that were true (which it isn't), it would have to be the case that (-56)9 = -512.

By my calculator, (-56)9 = -5416169448144896, so that's off by quite a bit. So what is the correct ninth root of -512? Hint: try factoring -512.
 
Thank D .mark
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
1K
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
14
Views
2K