Cos theta=pi/2 hint pi/2 is not an angle.

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Homework Help Overview

The problem involves the equation \(\cos\theta=\frac{\pi}{2}\), with a hint indicating that \(\frac{\pi}{2}\) is not an angle. Participants are exploring the implications of this equation within the context of trigonometric functions and their solutions.

Discussion Character

  • Exploratory, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the numerical approximation of \(\frac{\pi}{2}\) and its implications for the cosine function. There are attempts to evaluate the equation and questions about the nature of solutions, particularly regarding real versus complex numbers.

Discussion Status

The discussion is ongoing, with various interpretations being explored. Some participants suggest that there are no real solutions, while others consider the possibility of complex solutions. There is a recognition of the constraints imposed by the lesson's focus on real numbers.

Contextual Notes

Participants note that the problem may involve complex numbers, but the current lesson is focused on real solutions. There is an emphasis on the distinction between real and imaginary solutions in the context of the problem.

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cos theta=pi/2...hint pi/2 is not an angle.

Homework Statement


[tex]\cos\theta=\frac{\pi}{2}[/tex] HINT:The real number [itex]\frac{\pi}{2}[/itex] is not an angle.


Homework Equations





The Attempt at a Solution



I tried [itex]0=\cos^{-1} \frac{\pi}{2}[/itex], but that equals no solution.
And if [itex]\frac{\pi}{2}[/itex] were an angle the answer would be 0.

Am I solving this correctly?
 
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What is an approximate value for π/2 numerically?
 


[itex]\pi \approx 3.14[/itex] so [itex]\frac{\pi}{2}\approx 1.57[/itex]

and since [itex]\cos\theta=1.57, then...\theta=no solution, because: \cos\theta= -1\leq\theta\geq1[/itex]
 


Hi jrjack. Are you at all familiar with complex numbers?
 


I'm not sure, but NO SOLUTION is always one of the possible options.

Please explain further how to use complex numbers in this problem.
 


jrjack said:
I'm not sure, but NO SOLUTION is always one of the possible options.

Please explain further how to use complex numbers in this problem.

You might want to say no real solutions instead though.
 


Of course, No Real Solution. Since we are not dealing with imaginary numbers in this lesson, I think that is appropriate. Thanks.
 


jrjack said:
Of course, No Real Solution. Since we are not dealing with imaginary numbers in this lesson, I think that is appropriate. Thanks.

Yes that was my point exactly. :)


If you are only dealing with real numbers there is no solution. If you are allowed to use complex numbers (real and imaginary) then there are solutions.
 

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