Could I get a second pair of eyes on this?

  • Thread starter Thread starter dangerboyy
  • Start date Start date
  • Tags Tags
    Eyes Pair
Click For Summary

Homework Help Overview

The discussion revolves around a problem related to static equilibrium, specifically focusing on the forces acting on a system and the components of those forces, particularly the hinge's force and the tension in a cord.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between the vertical component of the hinge's force and the sum of vertical forces. Questions arise regarding the inclusion of tension in the calculations and how to balance forces in static equilibrium.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions, and providing guidance on how to approach the calculations. There is a recognition of the need to include additional components in the force balance, and some participants express a growing understanding of the concepts involved.

Contextual Notes

Some participants note the importance of adhering to the forum's homework template and express their status as new members, which may influence their familiarity with the discussion norms.

dangerboyy
Messages
8
Reaction score
0
OP warned about not using the homework template
1. Link to problem and the answer I got - https://ibb.co/ncGfDA

2. I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?


3. I attempted my answer (hopefully finished) in the link above
 
Last edited:
Physics news on Phys.org
dangerboyy said:
Link to full question and my answer at the bottom of text

I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?


https://ibb.co/ncGfDA
Hello @dangerboyy . :welcome:

Please use the homework template provided when you open a Thread.

For reference:
image.jpg
 

Attachments

  • image.jpg
    image.jpg
    26.4 KB · Views: 274
  • Like
Likes   Reactions: dangerboyy
SammyS said:
Hello @dangerboyy . :welcome:

Please use the homework template provided when you open a Thread.
Sorry, I'll keep this in mind. I'm a newby here who didn't pay enough attention to how to do the template, simply hoping my text would suffice.

edit - post is now in the proper template i believe
 

Attachments

  • image.jpg
    image.jpg
    32.3 KB · Views: 299
dangerboyy said:

Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?
 
  • Like
Likes   Reactions: dangerboyy
TSny said:
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?
That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?
 
The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?
 
  • Like
Likes   Reactions: dangerboyy
TSny said:
The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?
Well, ΣFx and ΣFy must both equal 0 in static equilibrium. How could I separate Fy in the positive direction among the cord and hinge?

edit - a light bulb turned on in my brain - Could I find Fy of the cord, then subtract from the total Fy in the positive direction to find that of the hinge?
 
dangerboyy said:
That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?

You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.
 
  • Like
Likes   Reactions: dangerboyy
Cutter Ketch said:
You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.
Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks
 
  • #10
dangerboyy said:
Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks
OK. Great! Welcome to PhysicsForums.
 
  • Like
Likes   Reactions: dangerboyy

Similar threads

Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
5
Views
2K