# Could I get a second pair of eyes on this?

OP warned about not using the homework template

2. I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?

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SammyS
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Link to full question and my answer at the bottom of text

I got an answer, but I was wondering if this is correct or not? Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?

https://ibb.co/ncGf DA
Hello @dangerboyy .

For reference:

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dangerboyy
Hello @dangerboyy .

Sorry, I'll keep this in mind. I'm a newby here who didn't pay enough attention to how to do the template, simply hoping my text would suffice.

edit - post is now in the proper template i believe

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TSny
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Am I correct to say (in part c) that the vertical component of the hinge's force will be equal to the sum of the vertical forces being exerted in the negative direction?
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?

dangerboyy
Not quite. Wouldn't you need to include the vertical component of FT in your calculation of (FH)y?
That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?

TSny
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The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?

dangerboyy
The system is in static equilibrium. So, what can you say about ΣFx and ΣFy?
Well, ΣFx and ΣFy must both equal 0 in static equilibrium. How could I separate Fy in the positive direction among the cord and hinge?

edit - a light bulb turned on in my brain - Could I find Fy of the cord, then subtract from the total Fy in the positive direction to find that of the hinge?

That's what I was thinking, but I wasn't exactly sure how to get an answer if I did so. May I request guidance?

You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.

dangerboyy
You’ve done everything correctly except when you balanced the vertical forces you forgot to include the tension. In exactly the same way you included Ft cos(30) in the horizontal forces add the vertical component into to equation with the vertical forces. It’s just one more term, and you already know the value.
Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks

TSny
Homework Helper
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Thanks! I believe I have this well understood now. Thanks to all others who helped me look past my stupidity as well. I'm brand new to this community, and this was a great first experience. Thanks
OK. Great! Welcome to PhysicsForums.

dangerboyy