Could someone PLEASE quickly check if my work is right?

  • Thread starter Thread starter Lawcheehung
  • Start date Start date
  • Tags Tags
    Work
Click For Summary
SUMMARY

The discussion centers on calculating the coefficient of friction for a system involving a 1.00 kg object and a 0.1487 kg object connected by a pulley. The user initially calculated the final velocity as 0.7295 m/s and the acceleration as 0.597957 m/s². However, a participant pointed out that the user incorrectly calculated the final velocity by neglecting gravitational acceleration. The correct approach involves using the equation Vfinal = Vinitial + at to account for the acceleration due to gravity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of kinematics and dynamics
  • Familiarity with friction concepts and calculations
  • Ability to apply equations of motion in physics
NEXT STEPS
  • Review the equations of motion, specifically Vfinal = Vinitial + at
  • Study the principles of friction and how to calculate the coefficient of friction
  • Explore the effects of gravitational force on connected systems
  • Practice problems involving pulleys and friction in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of friction and motion calculations.

Lawcheehung
Messages
2
Reaction score
0

Homework Statement


Basically there's a 1.00 kg object hanging in the air attached to a string which is attached to a 0.1487 kg object that is on a table, and they're connected with a pulley.

the 1.00 kg object pulls the 0.1487 kg a distance of 0.89 m in 1.22 s and then stops when it hits the ground, i need to find the coefficient of friction


ok so..


first i found the final velocity of the object
which is 0.89 m / 1.22 s which gave me a final velocity of 0.7295 m/s

then i found the acceleration of the entire body by doing

a = (vf - vi)/t which gave me an acceleration of 0.597957 m/s^2


The Fnet of the entire body is

Fnet = [(0.100kg ) + (0.1487kg )] * (0.597957 m/s^2)
= 0.14871 N
This is the actual net force with the friction



so the acceleration of the 0.100 kg falling down without the tension should be just

mg = (0.100)(9.8)
= 0.98 N


so the friction force should be
0.98 N - 0.14871 N
= 0.83129 N

This is the friction force.

The coefficient of friction is

Ff = uFn
so 0.83129 N = u(mg)
0.83129 N = u(0.1487 kg * 9.8 m/s^2)

u = 0.5704


Please i need help URGENT
 
Physics news on Phys.org


Well I can tell you that you got the final velocity wrong in your first equation. You completely ignored the fact that the object is accelerating under the force of gravity. What you did was the average velocity perhaps.
Try this: Vfinal = Vinitial + at
 

Similar threads

Replies
7
Views
2K
Replies
18
Views
3K
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
18K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K