MHB Could use some help for this statistics/math problem

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The discussion revolves around a user seeking urgent help with two statistics questions due tomorrow. They express confusion about determining the midpoint for the 31-40 and 41-50 intervals, questioning whether certain values are accurate. Additionally, they discuss their approach to assessing symmetry in a dataset, noting that they adjusted values to achieve a symmetric appearance. The user also critiques the presentation of a graph, suggesting it is poorly drawn and resembles a staircase. Overall, the user is looking for clarity and confirmation on their interpretations and calculations.
kimchuu
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Hello Everyone!
I really need help on 2 questions and it is due tomorrow! So please help me when u can and ASAP

1653533132259.png

So for this one, this was easy, except for the 31-40 interval I'm not sure if it's 4.5, cause it's not necessarily exactly between and half of 4 and 5 and for the 41-50 interval I'm not sure if its actually a 3 and its somewhat confusing. Does anyone care to enlighten me?
1653533246775.png

For this one, I am also confused. For my answer I believe it is approximately symmetric, you know what I did? So I did like what you usually do I add and replace the bars so all of them can look symmetric,
and then for the last one it stays as 12 and if I break/divide it by 2, you get 6, and that will be perfectly symmetric. The thing is I don't know if my thesis is correct.
PLEASE KINDLY
HELP ME ASAP
 
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I would say that the first one is just drawn badly! They did NOT have a fractional number of players on the floor! There were 2+ 1+ 4+ 3= 10 players.

For the next one, I have no idea what they mean by "shape"! I would probably say that this graph is shaped like a staircase!
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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