Coulomb's law and related problem

  • Thread starter Thread starter logearav
  • Start date Start date
  • Tags Tags
    Coulomb's law Law
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 5K views
logearav
Messages
329
Reaction score
0

Homework Statement



The sum of two point charges is 6µC. They attract each other with a force of 0.9 N, when kept 40 cm apart in vacuum. Calculate the charges.

Homework Equations





The Attempt at a Solution


q1+(-q2) = 6x10-6
q1-q2=6x10-6...I
q1=6x10-6+q2
According to Coulomb's law
F=q1q2/4πε0r2
.9=(6x10-6+q2)q2/4πε0(.4)2
.9=(6x10-6q2+q22)x9x109/.16
.144/9x109=6x10-6q2+q22
144x10-3x10-9/9=6x10-6q2+q22
q22+6x10-6q2-16x10-12=0
(q2+8x10-6)(q2-6x10-6)=0
q2=-8µC or q2=6µC
The answers given in the book are q1 = 8micro Coulomb and q2= -2 microcoulomb
I don't understand how to get this answer because when q2 = 8 microcoulomb and substituting in equation I , i get q1+8micro coulomb =6 micro coulomb so q1 should be -2 micro coulomb
Did i miss anything in the steps? Members, please help me .



 
Physics news on Phys.org
logearav said:

The Attempt at a Solution


q1+(-q2) = 6x10-6
q1-q2=6x10-6...I
q1=6x10-6+q2
Since you're assuming that q1 is positive and that q2 is negative, you don't need to wedge in that extra minus sign. Just write q1 + q2 = 6x10-6C.
According to Coulomb's law
F=q1q2/4πε0r2
.9=(6x10-6+q2)q2/4πε0(.4)2
Since one of the charges is negative the product q1*q2 will be negative, and thus the force should be negative also.

Let f = 0.9N, r = 0.40m, Q = 6μC, [itex]k = \frac{1}{4 \pi \epsilon_o}[/itex] Then

[itex]Q = q_1 + q_2[/itex] so that [itex]q_2 = Q - q_1[/itex]

[itex]f = -k \frac{q_1 q_2}{r^2} = -k \frac{q_1 (Q - q_1)}{r^2}[/itex]
 
it has been mentioned that two charges attract each other that's why i took q2 as negative. is my assumption wrong, sir?
 
logearav said:
it has been mentioned that two charges attract each other that's why i took q2 as negative. is my assumption wrong, sir?

No, the assumption is fine. Oppositely signed charges attract. Either q1 or q2 must be negative (but not both!).
 
Thanks a lot for the reply, sir. Then why i didn't get the correct answer when i framed the equation q1-q2= 6 micro coulomb, taking q1 as positive and q2 is negative. I got the correct answer when i proceeded as suggested by you. But what's wrong with my assumption?
 
logearav said:
Thanks a lot for the reply, sir. Then why i didn't get the correct answer when i framed the equation q1-q2= 6 micro coulomb, taking q1 as positive and q2 is negative. I got the correct answer when i proceeded as suggested by you. But what's wrong with my assumption?

q1 - q2 is the difference between the charges, not the sum of the charges.
 
I got it sir. Thanks a lot for patiently helping me.