- #1

omni-impotent

- 12

- 0

x' = -i*(b*t-a*t^2)*x - i*c*y

y' = -i*c*x - i*(a*t^2-b*t)*y;

where i^2 = -1.

These look like 2 coupled 1st order ODE, but are in fact 4 coupled 1st order due to the imaginary parts. Any hints?

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- Thread starter omni-impotent
- Start date

- #1

omni-impotent

- 12

- 0

x' = -i*(b*t-a*t^2)*x - i*c*y

y' = -i*c*x - i*(a*t^2-b*t)*y;

where i^2 = -1.

These look like 2 coupled 1st order ODE, but are in fact 4 coupled 1st order due to the imaginary parts. Any hints?

- #2

timthereaper

- 479

- 33

I'm not a mathematician, but why can't you solve one ODE and substitute into the other one?

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