- #1

- 12

- 0

x' = -i*(b*t-a*t^2)*x - i*c*y

y' = -i*c*x - i*(a*t^2-b*t)*y;

where i^2 = -1.

These look like 2 coupled 1st order ODE, but are in fact 4 coupled 1st order due to the imaginary parts. Any hints?

- Thread starter omni-impotent
- Start date

- #1

- 12

- 0

x' = -i*(b*t-a*t^2)*x - i*c*y

y' = -i*c*x - i*(a*t^2-b*t)*y;

where i^2 = -1.

These look like 2 coupled 1st order ODE, but are in fact 4 coupled 1st order due to the imaginary parts. Any hints?

- #2

- 479

- 32

I'm not a mathematician, but why can't you solve one ODE and substitute into the other one?

- Replies
- 5

- Views
- 11K

- Replies
- 2

- Views
- 7K

- Replies
- 11

- Views
- 38K

- Last Post

- Replies
- 4

- Views
- 2K

- Replies
- 1

- Views
- 2K

- Replies
- 2

- Views
- 1K

- Replies
- 1

- Views
- 1K

- Last Post

- Replies
- 0

- Views
- 3K

- Replies
- 8

- Views
- 7K

- Last Post

- Replies
- 1

- Views
- 3K