Covariant Derivative Wrt Superscript Sign: Explained

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SUMMARY

The discussion clarifies the behavior of the covariant derivative concerning superscript indices in tensor calculus. Specifically, it establishes that when taking the covariant derivative of a tensor with respect to a superscript, the partial derivative term does not inherently carry a minus sign; rather, the sign is influenced by the Christoffel symbols and the metric tensor, denoted as ##g_{\mu\nu}##. Additionally, it is confirmed that the covariant derivative does not always have an index opposite to that of the tensor being differentiated, allowing for flexibility in index positioning due to the properties of the metric.

PREREQUISITES
  • Understanding of tensor calculus and its notation
  • Familiarity with Christoffel symbols and their role in general relativity
  • Knowledge of metric tensors, specifically ##g_{\mu\nu}##
  • Basic concepts of covariant differentiation
NEXT STEPS
  • Study the properties and applications of Christoffel symbols in tensor calculus
  • Explore the concept of nonmetricity in general relativity
  • Learn about the implications of index gymnastics in tensor differentiation
  • Investigate the relationship between covariant and contravariant tensors
USEFUL FOR

This discussion is beneficial for physicists, mathematicians, and students studying general relativity or advanced topics in differential geometry, particularly those focusing on tensor analysis and covariant differentiation.

cr7einstein
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Dear all,
I was reading this https://sites.google.com/site/generalrelativity101/appendix-c-the-covariant-derivative-of-the-ricci-tensor, and it said that if you take the covariant derivative of a tensor with respect to a superscript, then the partial derivative term has a MINUS sign. How? The Christoffel symbol should have a minus sign, but I don't understand how does the partial derivative get one?

Also, does covariant derivative always have an index opposite to that of the tensor(e.g. a contravariant tensor will be differentiated wrt a covariant tensor, and a covariant tensor wrt to a covariant index)? If so, why? Is there a relation between the two(which the minus sign mentioned above indicates)?
Thanks in advance!
 
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cr7einstein said:
How? The Christoffel symbol should have a minus sign, but I don't understand how does the partial derivative get one?

None of that is correct actually. ##\nabla^{\mu}A^{\nu} = g^{\mu\delta}\nabla_{\delta}A^{\nu} = g^{\mu\delta}\partial_{\delta}A^{\nu} + g^{\mu\delta}\Gamma^{\nu}_{\delta \sigma}A^{\sigma}## and similarly for tensors of arbitrary rank, so it depends entirely on ##g_{\mu\nu}##.

cr7einstein said:
Also, does covariant derivative always have an index opposite to that of the tensor(e.g. a contravariant tensor will be differentiated wrt a covariant tensor, and a covariant tensor wrt to a covariant index)?

No.
 
I'm afraid you didn't choose a bright source for reading. So, in general relativity there's no x_{\mu} (and in special relativity shouldn't be either). Next:

\nabla^{\mu} T_{\alpha} = g^{\mu\beta}\nabla_{\beta}T_{\alpha}

is just a shorthand whenever necessary. Because the nonmetricity is 0, then you can play around freely with the position of the index in the covariant derivative. The metric also allows you to play with the index position also for the tensorial objects being differentiated:

\nabla^{\mu}T_{\alpha}^{~~\gamma} = g_{\alpha\delta} g^{\mu\lambda}\nabla_{\lambda}T^{\delta\gamma}

Relativists call this 'idex gymnastics'.
 

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