Cp/Cv Value for Water Vapor and Hydrogen Gas at 2755 K

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Homework Help Overview

The discussion revolves around determining the Cp/Cv value for water vapor and hydrogen gas at a temperature of 2755 K, with a specified molar ratio of H2O to H2. Participants are seeking specific heat capacity values for water vapor at this temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find Cp and Cv values for water vapor at 2755 K and expresses a desire for accurate answers. Some participants provide equations and calculations for Cp, while others mention the absence of Cv equations in their references.

Discussion Status

Participants are actively sharing equations and calculations related to Cp for water vapor, with some suggesting approximations for Cv. There is a mix of approaches being explored, and while some values have been calculated, there is no explicit consensus on the final Cp/Cv ratio.

Contextual Notes

One participant notes that the equation for Cp is valid only within a specific temperature range, raising questions about its applicability at 2755 K. Additionally, there is mention of unit conversions that need to be considered in the calculations.

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I need to find out the Cp/Cv value for Water Vapor and Hydrogen gas at 2755 K and a molar ratio of: H2O/H2:48.6112/62.5 I would at least like the Cv and Cp values for water vapor at 2755 K. A correct answer will be greatly appreciated.
 
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from the equation in my thermodynamic textbook this is my equation

Cp(T) steam = 32.24 + 0.1923e-2*T + 1.055e-5*T^2 - 3.595e-9*T^3

However, there are a few things i need to mention here

First the units are kJ/kmol-K so you need to divide by 18 to get kJ/kg-K

Also, this equation is over the range of 273K - 1800K with a maximum error of 0.53%, so its pretty small, If i use the same equation at 2755 K I get

Cp(2755) Steam = 42.4393 kJ/kmol-K or

Cp(2755) Steam = 2.35 kJ/kg-K

As for the Cv values, my text does not have an equation
 
I have a computer database that's giving me 1.257
 
abercrombiems02 said:
...

Cp(2755) Steam = 42.4393 kJ/kmol-K or ...

As for the Cv values, my text does not have an equation
You could use Cp - Cv = R = 8.314 kJ/K-kmol, as a pretty good approximation.

So, Cv = 42.439 - 8.314 = 34.125 kJ/K-kmol

Hence, Cp/Cv = 1.244, which is not too far from the number quoted by Q_Goest.
 

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