Crazy Circle Illusion: Amaze Your Friends!

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Discussion Overview

The discussion revolves around the "Crazy Circle Illusion," exploring the visual effects and mathematical principles behind the motion of an octagon within a circle. Participants engage in calculations related to the paths traced by vertices and the geometric relationships involved.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants suggest that the illusion may be a trick of the eye and invite calculations of the actual path traversed by the vertices of an octagon.
  • One participant describes the mathematical basis for drawing a circle using cosine and sine functions, proposing that phase differences can create circular motion.
  • Another participant theorizes that the inner polygon has half the radius of the outer circle, detailing the motion of a point on the inner circle as it rolls inside the outer circle.
  • This participant provides a mathematical derivation of the coordinates of the tracked point, explaining how the angles relate to the motion of the circles.
  • A later reply references a related thread on programming puzzles, noting the variations and animations created through phase adjustments and questioning the potential for coherent aperiodic animations.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the illusion, with some focusing on the mathematical aspects while others emphasize the visual perception. No consensus is reached regarding the underlying principles or the best approach to understanding the illusion.

Contextual Notes

Some mathematical steps and assumptions in the derivations are not fully resolved, and the discussion includes varying interpretations of the visual effects involved.

kaliprasad
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Surely this must be tricks of the eye? Anyone up for calculating the real path traversed by the vertices of an octagon when in such a motion?
 
mathbalarka said:
Surely this must be tricks of the eye? Anyone up for calculating the real path traversed by the vertices of an octagon when in such a motion?

You can draw a circle with a cosine horizontally and a sine vertically.
This is how a cosine and a sine are defined on the unit circle.
It makes sense that if you create a whole bunch of sines on straight lines with the proper phase differences, that you'd get a circle.
 
Mesmerizing! :D

I have embedded the video so people can just watch it here.
 
I think the "trick" to this is that the "inner circle" (polygon) has exactly half the radius of the outer circle.

Imagine we trace the path of a point on a circle of radius $r$ as it travels inside a circle of radius $2r$. Since it doesn't really matter "when" we start tracking it (the path is periodic), assume that both circles are touching at the point $(0,2r)$ at $t = 0$, and that the outer circle is centered at the origin.

As the inner circle "rolls" counter-clockwise, the point on the inner circle we are tracking moves CLOCKWISE around a shifting center.

This center is at: $((2r-r)\cos t,(2r-r)\sin t) = (r\cos t,r\sin t)$. Since the outer circle's circumference (which is directly proportional to radius) is twice that of the inner circle, as the center has moved through an angle of $t$, the point we are tracking makes an angle of $2t$ with the point of tangency. Half of this angle is $t$, the other half is the angle our tracked point makes to a horizontal line passing through the center of the inner circle.

It follows our tracked point has coordinates:

$(r\cos(-t),r\sin(-t)) + (r\cos t,r\sin t) = (2r\cos t,0)$.

As $t$ varies, the image $\{(x(t),y(t)): t \in \Bbb R_0^+\}$ is the interval $[-2r,2r]\times \{0\}$, which is a "straight-line" (segment).
 

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