rymatson406
- 3
- 0
(p ^ q) ->(p ▼ ~q)
Need help creating a truth table (6 columns) for the above.Thanks
Need help creating a truth table (6 columns) for the above.Thanks
. . . . \begin{array}{|c|c|c|c|c|c|c|c|c|} <br /> p & q & (p & \wedge & q) & \to & (p & \vee & \sim q) \\ \hline<br /> T&T & T&T&T &T& T&T&F \\<br /> T&F &T&F&F &T& T&T&T \\<br /> F&T &F&F&T &T& F&F&F \\<br /> F&F & F&F&F &T& F&T&T \\ \hline<br /> && 1&2&1&3&1&2&1 \\ \hline \end{array}**Create a truth table for: .(p \wedge q)\;\to\;(p \,\vee \sim q)