Creating a .0500 M HCl Calculation Help

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To create a 0.0500 M solution of hydrochloric acid from a 0.5000 M stock solution, the dilution equation M1 x V1 = M2 x V2 is applicable. The student needs 400 mL of the dilute solution but can prepare 500 mL due to the flask size. This requires careful calculation to determine the volume of the concentrated solution needed. The discussion highlights the importance of understanding both the calculation and the constraints of available lab equipment. Proper forum etiquette is also emphasized, noting the need to post homework questions in designated areas.
Bashyboy
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Hi, I have a problem regarding a lab question. It goes as follows:

A student required .0500 M solution of hydrochloric acid, HCl, and has on hand a .5000 M solution. Calculate how much more of the concentrated solution, in mL units, must be pipetted if 400 mL of dilute solution are required, and a 500 mL volumetric flask is the only one available.

Am I simply to use the M1 x V1 = M2 x V2 equation?

Thank you
 
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Bashyboy said:
Am I simply to use the M1 x V1 = M2 x V2 equation?

It will do. Beware - question is tricky. Not in terms of difficult calculations, more like a brain teaser.

Please ask HW and HW type questions in homework & coursework forums.
 
The student "requires" 400 ml. of the resulting dilute solution, but because he only has a 500 ml. volumetric flask, he may choose to prepare 500 ml. of the dilute solution.
 
Thank you both. And I am sorry; I didn't know there was a separate form for homework questions, thank you for letting me know.
 

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