Creating a .0500 M HCl Calculation Help

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Discussion Overview

The discussion revolves around a lab question involving the preparation of a .0500 M hydrochloric acid (HCl) solution from a .5000 M stock solution. Participants explore the calculations needed to determine the volume of the concentrated solution required to achieve the desired dilution, considering the constraints of using a 500 mL volumetric flask.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant suggests using the equation M1 x V1 = M2 x V2 to find the required volume of the concentrated solution.
  • Another participant notes that the question is tricky, indicating that it may involve more than straightforward calculations.
  • A third participant points out that while the student requires 400 mL of dilute solution, the use of a 500 mL volumetric flask allows for the possibility of preparing 500 mL instead.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact approach to the problem, and there are differing views on the implications of the flask size and the volume of dilute solution required.

Contextual Notes

The discussion does not clarify the assumptions regarding the preparation of the solution or the implications of using a 500 mL flask for a 400 mL requirement.

Bashyboy
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Hi, I have a problem regarding a lab question. It goes as follows:

A student required .0500 M solution of hydrochloric acid, HCl, and has on hand a .5000 M solution. Calculate how much more of the concentrated solution, in mL units, must be pipetted if 400 mL of dilute solution are required, and a 500 mL volumetric flask is the only one available.

Am I simply to use the M1 x V1 = M2 x V2 equation?

Thank you
 
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Bashyboy said:
Am I simply to use the M1 x V1 = M2 x V2 equation?

It will do. Beware - question is tricky. Not in terms of difficult calculations, more like a brain teaser.

Please ask HW and HW type questions in homework & coursework forums.
 
The student "requires" 400 ml. of the resulting dilute solution, but because he only has a 500 ml. volumetric flask, he may choose to prepare 500 ml. of the dilute solution.
 
Thank you both. And I am sorry; I didn't know there was a separate form for homework questions, thank you for letting me know.
 

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