- #1
KFC
- 488
- 4
For creation operator of hamonic oscillator, we have
[tex]a^\dagger |n> = \sqrt{n+1}|n+1>[/tex]
if I consider the creation operator operate on the bar vector, should I also get the same thing? namely
[tex]<n|a^\dagger = \sqrt{n+1}<n+1|[/tex]
[tex]a^\dagger |n> = \sqrt{n+1}|n+1>[/tex]
if I consider the creation operator operate on the bar vector, should I also get the same thing? namely
[tex]<n|a^\dagger = \sqrt{n+1}<n+1|[/tex]