Cross Product Confusion: Solving UxV

[likephysics]

I was reading div grad curl and all that. Couldn't get something basic - cross product.

U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)

UxV = [ -i df/dx - j df/dy + k] uxvy

can't figure out how to get U x V.

 

[tiny-tim]

Hi likephysics!

(have a curly d: ∂ and try using the X₂ tag just above the Reply box )

I was reading div grad curl and all that. Couldn't get something basic - cross product.

U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)

UxV = [ -i df/dx - j df/dy + k] uxvy

can't figure out how to get U x V.

(Let's ignore the common factor, u_xv_y)

The i component of UxV is U_jV_k - V_jU_k, = 0 - ∂f/∂x.

Can you do the others now? ​

 

[likephysics]

Thanks a bunch. Now I feel less stupid. yay!