Cross Product Confusion: Solving UxV

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SUMMARY

The discussion centers on calculating the cross product of two vector fields, U and V, represented in component form. The vectors are defined as U = iux + k df/dx (ux) and V = jvy + k df/dy (vy). The resulting cross product U x V is derived as UxV = [ -i df/dx - j df/dy + k] uxvy, with the i component specifically calculated as UjVk - VjUk, resulting in 0 - ∂f/∂x. The conversation highlights the confusion surrounding the application of vector calculus in this context.

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  • Understanding of vector calculus concepts, specifically cross products
  • Familiarity with the notation for partial derivatives (∂)
  • Knowledge of vector field representation in component form
  • Basic proficiency in mathematical operations involving vectors
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likephysics
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I was reading div grad curl and all that. Couldn't get something basic - cross product.

U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)

UxV = [ -i df/dx - j df/dy + k] uxvy

can't figure out how to get U x V.
 
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Hi likephysics! :smile:

(have a curly d: ∂ and try using the X2 tag just above the Reply box :wink:)
likephysics said:
I was reading div grad curl and all that. Couldn't get something basic - cross product.

U = iux + k df/dx (ux)
V = jvy + k df/dy (vy)

UxV = [ -i df/dx - j df/dy + k] uxvy

can't figure out how to get U x V.

(Let's ignore the common factor, uxvy)

The i component of UxV is UjVk - VjUk, = 0 - ∂f/∂x.

Can you do the others now? :smile:
 
Thanks a bunch. Now I feel less stupid. yay!
 

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