Cumulative distribution function problem question?

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SUMMARY

The discussion focuses on calculating the joint cumulative distribution function (CDF) of three independent random variables A, B, and C, each uniformly distributed over the interval (0,1). The joint CDF is established as F(A,B,C) = abc, derived from the integration of the uniform probability density function. The second part of the problem involves determining the probability that all roots of the quadratic equation Ax² + Bx + C = 0 are real, which requires the condition b² - 4ac ≥ 0. The user attempts to solve this using a triple integral but encounters issues with the probability exceeding 1.

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  • Understanding of cumulative distribution functions (CDF)
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  • Familiarity with quadratic equations and the discriminant
  • Basic skills in multivariable calculus, particularly triple integrals
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DavidGuimont
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Hi, so this is the example I have:

Suppose that A, B, C are independent random variables, each being uniformly distributed over (0,1).

(a) What is the joint cumulative distribution function of A, B, C?

(b) What is the probability that all of the roots of the equation Ax^2 + Bx +C=0 are real?

Okay so for a), I think I get this since they are independent and are all uniformly distributed, their probability density function is still just 1. Then to get get the cumulative distribution function I just integrate this from 0 to a, 0 to b, 0 to c, which gives me just F(A,B,C)=abc which makes sense to me (I think).

I'm just lost as to what to do with b), I guess the point to have the roots be real, is it just that I have to have b^2 - 4ac be positive? So that the square roots of this can be found? This is a question in a textbook and so I still tried something which I'm sure is very wrong. I tried a triple integral having my borders be integrating from (-2sqrt(ac) to 2sqrt(ac))db (because you want b^2-4ac to be greater than or equal to 0). Then just integrating from 0 to 1 according to a and 0 to 1 according to b. If anyone has tips, solutions to help me out it would be greatly appreciated as I get a probability that is greater than 1 -_- . Thank you very much! :)
 
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\int\int(\int_{\sqrt{4ac}}^1 db)dadc=\int\int(1-2\ sqrt(ac))dadc. The limits for a and c are a little messy. You need both non negative while ac < 1/4.
 

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