MHB Current Equivalence at a Circuit Node

[Dustinsfl]

Given the circuit below:

Why does KCL equate to
\[
\frac{e - v_c}{R_1} = C\frac{dv_c}{dt} + f(v_c) + i_L
\]

 

[I like Serena]

Given the circuit below:

Why does KCL equate to
\[
\frac{e - v_c}{R_1} = C\frac{dv_c}{dt} + f(v_c) + i_L
\]

KCL says that in any node current in equals current out.

In the node at the top, the current through $R_1$ is coming in, which must therefore be equal to the current going out and into the capacitor plus the current through the non-linear resistor plus the current through the coil.

 

[Dustinsfl]

KCL says that in any node current in equals current out.

In the node at the top, the current through $R_1$ is coming in, which must therefore be equal to the current going out and into the capacitor plus the current through the non-linear resistor plus the current through the coil.

I still don't quite understand. Can you be more specific by node at the top and the currents you mention?