De Broglie Relations Confusion

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SUMMARY

The discussion centers on the confusion surrounding the de Broglie relations in quantum mechanics, specifically the equations ##p = \frac{h}{\lambda}## and ##E = hf##. The user initially attempted to derive the relationship between energy and momentum using the energy-momentum relation but encountered inconsistencies. The resolution involved recognizing the distinction between phase velocity and group velocity, with the latter being the correct velocity for particles in de Broglie mechanics. The correct dispersion relation for free Schrödinger waves was also highlighted, clarifying the relationship between frequency and wavelength.

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lekh2003
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I've been attempting to run through some quantum mechanics and I've seen something extremely odd, and I just can't spot my mistake.

I know the relationships: ##p = \frac{h}{\lambda}## and ##E = hf##. I also know the relationship ##E = \frac{p^2}{2m}##.

I tried to show using the energy-momentum relation and the de Broglie wavelength equation that ##E = hf## is true, but its simply inconsistent.

\begin{align}
E &= \frac{p^2}{2m}\\
&= \frac{(\frac{h}{\lambda})^2}{2m}\\
&= \frac{(\frac{hf}{v})^2}{2m}\\
&= \frac{\frac{E^2}{v^2}}{2m}\\
&= \frac{E^2}{2mv^2}\\
&= \frac{E^2}{2(\frac{h}{\lambda})v}\\
&= \frac{E^2}{2E}\\
&= \frac{E}{2}
\end{align}

Where am I messing this up?
 
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You've used the phase velocity: ##v_p = f\lambda = \frac{v}{2}##.

In the de Broglie mechanics it's the group velocity that is the velocity of the particle: ##v_g = v##.
 
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Thank you so much! Everything makes sense now, I read up some more on a StackExchange thread.
 
In other words you need to use the correct dispersion relation for free Schrödinger waves, which results from
$$E=\hbar \omega = \frac{p^2}{2m}=\frac{(\hbar k)^2}{2m},$$
i.e.,
$$\omega = \frac{\hbar}{2m} k^2.$$
In your notation it's
$$2 \pi f=\frac{h}{4 \pi m} \frac{(2 \pi)^2}{\lambda^2} \; \Rightarrow \; f=\frac{h}{2m \lambda^2}.$$
 
The neighborhood of an event includes points that are timelike, null, and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still ##R^4## even though the metric on it is not the one induced by that topology. Thanks
 
iosman001 said:
The neighborhood of an event includes points that are timelike, null, and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still ##R^4## even though the metric on it is not the one induced by that topology. Thanks
Did you attach this post to the wrong thread? It looks off-topic here.
 
iosman001 said:
The neighborhood of an event includes points that are timelike, null and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still R4R4R^4 even though the metric on it is not the one induced by that topologyhttps://chatavenue.vipThanks

thanks my issue has been fixed.
 

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