- #1

Deathfrost

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## Homework Statement

I am trying to calculate the angular momenta for

[itex] \psi(x,y,z) = A(ar^2 + bz^2) [/itex]

A is given as a constant.

## Homework Equations

## The Attempt at a Solution

I know that [itex] z=r\sqrt{4\pi/3} * Y_0^1 [/itex]

What I have so far is:-

[itex] \psi(x,y,z) = r^2Aa + r^2b\sqrt{4\pi/3} * Y_0^1) [/itex]

and thus one of the possible values of momentum is hbar since l is one. but how do I deal with the constant part added to the equation, the A*a*r^2 when I try to calculate the probability?

A problem like [itex] \psi(x,y,z) = A(x+y+2z)*exp^{-ar} [/itex] I can deal with, since everything is multiplied across by the same constant, that just differ by some known factor. When I try to find the probability, and divide each angular part, the constants cancel out.

Thanks for any help