Decay and Atoms: Calculating Mo-99 Requirements at Equilibrium - 1x10^9 Atoms"

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The discussion centers on calculating the amount of molybdenum-99 (Mo-99) required to produce 100 MBq of technetium-99m (Tc-99m) under equilibrium conditions. The calculation provided is based on the formula 67/6.4 * 1x10^8, resulting in 1 x 10^9 atoms of Mo-99 needed. Participants emphasize the importance of posting homework questions in the appropriate sub-forums, specifically "Advanced Physics," and encourage showing work for clarity.

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100mbq tc 99 requires how much mo 99? Answer in number of atoms, assume equilibrium conditions:
67/6.4 *1x10^8 = 1 x10^9
 
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Please post homework questions in the Homework forum and follow the guidelines there. Thank you.
 
Yes, this belongs in one of the "Homework and Coursework Questions" sub-forums, probably "Advanced Physics." Please re-post there, and show some work or at least thoughts about it.
 

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