Decimal points different in these two answers

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The discussion revolves around discrepancies in scientific notation answers provided by a teacher, specifically regarding the placement of decimal points. The numbers 2445859.873 and 254777070.1 were compared, with the teacher's answers being 2.44x10^6 and 254.6x10^6, which were deemed incorrect due to rounding errors. Correct rounding would yield 2.45x10^6 and 254.8x10^6, respectively, depending on the significant figures required. There is speculation that the teacher may have used the notation with 10^6 for consistency in unit conversion, such as from microseconds to seconds. Overall, the conversation highlights the importance of accurate rounding and the potential reasoning behind the notation choices.
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Homework Statement
Result in decimal point
Relevant Equations
go back or forward with the point
I have two answers and somehow the answers have the decimal point in different place.

2445859.873 with the answer of 2.44x106

and

254777070.1 with the answer of 254.6x106

why the teacher do that ?
 
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Lnewqban said:
Perhaps the teacher wanted to cancel ##10^6## in some operation?

Please, see:
https://en.wikipedia.org/wiki/Scientific_notation

:cool:

I understand why it is used but why 254777070.1 with the answer of 254.6x106 and not 2.55x108?
 
chriscarson said:
2445859.873 with the answer of 2.44x106
and
254777070.1 with the answer of 254.6x106

Your teacher has not rounded those numbers correctly 😜
 
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etotheipi said:
Your teacher has not rounded those numbers correctly 😜

we find mistakes in their work so nothing new.
 
@chriscarson are ##123000##, ##123 \times 10^3## and ##1.23 \times 10^5## all the same number?
 
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chriscarson said:
I have two answers and somehow the answers have the decimal point in different place.

2445859.873 with the answer of 2.44x106

and

254777070.1 with the answer of 254.6x106

why the teacher do that ?
Were your answers 2445859.873 and 254777070.1?
If the teacher's answers were 2.44x106 and 254.6x106, then I believe that your answers or the teacher's answers might have been slightly off. To three significant digits, 2445859.873 would be 2.45 x 106, and to four significant digits, 254777070.1 would be 254.8 x 106.

As already mentioned, writing both numbers times 106 might have been done for some reason that you didn't mention.
 
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etotheipi said:
@chriscarson are ##123000##, ##123 \times 10^3## and ##1.23 \times 10^5## all the same number?

so I would have a good answer with both 254.6x106 and 2.55x108 when I have 254777070.1 on the calculator ?
 
Assuming you fix the dodgy rounding, then yeah!
 
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  • #10
chriscarson said:
so I would have a good answer with both 254.6x106 and 2.55x108 when I have 254777070.1 on the calculator ?
No for your first answer. It would be 254.8x106
 
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  • #11
Mark44 said:
Were your answers 2445859.873 and 254777070.1?
If the teacher's answers were 2.44x106 and 254.6x106, then I believe that your answers or the teacher's answers might have been slightly off. To three significant digits, 2445859.873 would be 2.45 x 106, and to four significant digits, 254777070.1 would be 254.8 x 106.

As already mentioned, writing both numbers times 106 might have been done for some reason that you didn't mention.

yeah probably there is something that she prefers x106 that she doesn t said why.
 
  • #12
Mark44 said:
No for your first answer. It would be 254.8x106

2.55x108 would also be good ?
 
  • #13
chriscarson said:
2.55x108 would also be good ?
Yes, depending on how many significant figures are required.
 
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  • #14
etotheipi said:
Assuming you fix the dodgy rounding, then yeah!

dodgy I guess you mean the mistake
 
  • #15
Mark44 said:
Yes, depending on how many significant figures are required.

it s not asked , ok so thanks
 
  • #16
thanks all...
 
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  • #17
2445859.873 → 2.44x10⁶ is wrong.
2445859.873 → 2.45x10⁶ is correct if rounding to 3 sig. figs.

254777070.1 → 254.6x10⁶ is wrong
254777070.1 → 254.8x10⁶ is correct if rounding to 4 sig. figs.
(But it is not 'standard form' and it would be more usual to express it as 2.548x10⁸ if 4 sig. are required,)

However there might be a reason for using 10⁶ in both cases. If (for example) your initial values were in units of μs and you wanted the final answers in seconds, it would be helpful to use 10⁶ for both. Then the answers would simply be 2.45s and 254.8s
 
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  • #18
Steve4Physics said:
2445859.873 → 2.44x10⁶ is wrong.
2445859.873 → 2.45x10⁶ is correct if rounding to 3 sig. figs.

254777070.1 → 254.6x10⁶ is wrong
254777070.1 → 254.8x10⁶ is correct if rounding to 4 sig. figs.
(But it is not 'standard form' and it would be more usual to express it as 2.548x10⁸ if 4 sig. are required,)

However there might be a reason for using 10⁶ in both cases. If (for example) your initial values were in units of μs and you wanted the final answers in seconds, it would be helpful to use 10⁶ for both. Then the answers would simply be 2.45s and 254.8s

yes it shows like you are saying , they are both x106, thanks.
 
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