Decomposing Rank-2 Tensors in Dirac's "General Theory of Relativity

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Discussion Overview

The discussion revolves around the decomposition of rank-2 tensors as presented in Dirac's "General Theory of Relativity." Participants explore the implications of Dirac's statements regarding the expressibility of tensors as sums of outer products, seeking clarification and explanations of the concept.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants reference Dirac's assertion that a general rank-2 tensor can be expressed as a sum of outer products, questioning whether this is an obvious statement.
  • A participant proposes a definition of a rank-2 tensor using the notation of tensor products, suggesting a way to express the tensor in terms of vectors.
  • Another participant expresses uncertainty about the notation used and asks for an explanation based solely on Dirac's definitions.
  • Several participants discuss issues with LaTeX formatting in the posts, indicating a technical challenge in presenting mathematical expressions clearly.
  • One participant offers a detailed approach to the decomposition, explicitly writing out the summation and defining the vectors involved, suggesting that the construction is straightforward.

Areas of Agreement / Disagreement

There is no consensus on whether Dirac's decomposition is obvious, as participants express varying levels of familiarity with the notation and concepts involved. The discussion remains unresolved regarding the clarity and implications of the decomposition.

Contextual Notes

Participants note issues with LaTeX rendering that may affect the clarity of mathematical expressions. There are also varying interpretations of Dirac's definitions and the notation used in the discussion.

Kostik
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TL;DR
Dirac says that a general rank-2 tensor ## T^{\mu\nu} ## can be decomposed as ## A^\mu B^\nu + A'^\mu B'^\nu + A''^\mu B''^\nu + \cdots\, ##. Is this obvious?
Dirac's book "General Theory of Relativity" says on p. 2 that a general rank-2 tensor can be written as a sum of outer products: $$ T^{\mu\nu} = A^\mu B^\nu + A'^\mu B'^\nu + A''^\mu B''^\nu + \cdots $$ Importantly, he repeats this on p. 18, in developing the covariant derivative, where he mentions that a tensor ## T_{\mu\nu} ## is "expressible as a sum of terms like ## A_\mu B_\nu ##".

Is this obvious? Can someone show or explain this?
 
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Kostik said:
TL;DR Summary: Dirac says that a general rank-2 tensor can be decomposed: ##T^\mu\nu = A^\mu B^\nu + A'^\mu B'^\nu + A''^\mu B''^\nu + ...##. Is this obvious?

Dirac's book "General Theory of Relativity" says on p. 2 that a general rank-2 tensor can be written as a sum of outer products:

$$T^\mu\nu = A^\mu B^\nu + A'^\mu B'^\nu + A''^\mu B''^\nu + ...$$

Importantly, he repeats this on p. 18, in developing the covariant derivative, where he mentions that a tensor ##T_\mu\nu$ is "expressible as a sum of terms like $A_\muB_\nu##".

Is this obvious? Can someone show or explain this?
By definition, a tensor of rank two can be written as
$$
T = T^{\mu\nu} e_\mu \otimes e_\nu
$$
We can introduce the vectors ##A^\nu = T^{\mu\nu} e_\mu## and ##B_\nu = e_\nu## (note that here ##\nu## is being used as a counter rather than a component index) and therefore
$$
T = A^\nu \otimes B_\nu
$$
 
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I'm not familiar with your notation, I wonder if Dirac's decomposition can be explained using only his definition of tensors.
 
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Kostik said:
I added the missing braces, but the LaTex still doesn't seem to be working in the original post.
It's a known issue when you make the first post to use LaTeX (OP or reply) on a page. The parser doesn't get loaded until you refresh the page. Your LaTeX looks fine to me, and will look fine to you once you've hit refresh.
 
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Ibix said:
It's a known issue when you make the first post to use LaTeX (OP or reply) on a page. The parser doesn't get loaded until you refresh the page. Your LaTeX looks fine to me, and will look fine to you once you've hit refresh.
Aha, yes, I see it now.
 
Oh, I think it's actually fairly straightforward. Write (showing the summation explicitly): $$T^{\mu\nu}=\sum_{\lambda,\kappa}T^{\lambda\kappa}{\delta_\lambda}^\mu{\delta_\kappa}^\nu \,\,\,\,\text{(no Einstein summation)}$$ Then ##A^\mu = T^{\lambda\kappa}{\delta_\lambda}^\mu## (not summed over ##\lambda##) and ##B^\nu={\delta_\kappa}^\nu##. (Regard ##\lambda## and ##\kappa## as fixed.) Since everything in sight is a tensor, the ##A^\mu## and ##B^\nu## are obviously vectors (no need to worry about constructing a non-vector).
 

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