Definition of radius of sight optics

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Homework Help Overview

The discussion revolves around the concept of the "radius of sight" in optics, particularly in the context of a fish underwater and how it perceives the external world through the water's surface. Participants are exploring the implications of light refraction and total internal reflection on visibility from underwater.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to define the radius of sight and its significance, with some questioning how light refraction affects visibility. Others are exploring the geometry of light paths and the critical angle for total internal reflection.

Discussion Status

The discussion is active, with participants providing insights and visual aids to enhance understanding. There is a focus on tracing light paths and applying Snell's law, although no consensus has been reached on the exact definition or calculation of the radius of sight.

Contextual Notes

Some participants express uncertainty about the concepts involved, suggesting that visual representations may aid comprehension. The discussion also highlights the need to consider angles of incidence and the conditions for light to escape the water.

Werg22
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"A fish is 3 meters underwater. What is the fish's sight radius of the external world?"

My question is what is the definition of this radius? What does it mean?
 
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If you consider the refraction of light entering the water, you'll realize that any light that makes it to the fish's eye must enter the water within a circle at the water's surface. Find the radius of that circle.
 
If you look up towards the surface from within a swimming pool you will find that a circular region appears on the surface of the pool where you can see what is outside of the pool. Outside of this circular region you cannot see what is above the surface. This circle is centered on a point right above you and its existence can be explained with total internal reflection.
 
I'm not sure if I understand (a quick drawing might be helpfull) but if I do, I have to calculate the distance between the fish and a point on the surface of the water where a ray that is parrallel to a straight line between the fish and that same point is not refracted?
 
A ray traveling from the eye of the fish to point p on the surface are incident at the surface of the ocean at the critical incident angle [itex]\alpha_c[/itex]. Beyond this point total internal reflection will take place and rays cannot enter from above the surface into the eye of the fish.
 

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andrevdh has provided a picture that will surely help, but I suggest you try the following to understand what's going on. Imagine the fish's head to be replaced by a light bulb emitting light in all directions. Trace the path of several of these rays as they refract into the air (apply Snell's law of refraction) and see what you can deduce. Start with rays that are nearly vertical (small angle of incidence) and then slowly increase the angle of incidence and see what happens to the refracted ray in air. You'll find, as andrevdh states, that after some critical angle of incidence the light from the bulb (on the fish's head) won't make it out of the water.

Then realize that the light coming from outside the water to the fish's eye must follow these same paths but in reverse.
 

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