Denseness of bounded funtions in L^2?

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SUMMARY

The space of infinitely differentiable functions with bounded derivatives, denoted as C_b^\infty(\mathbb{R}^n), is indeed dense in L^2(\mathbb{R}^n). This conclusion is supported by the fact that C_b^\infty(\mathbb{R}^n) includes C_0^\infty(\mathbb{R}^n), which is known to be dense in L^p(\mathbb{R}^n). However, certain functions, such as f(x)=1, exist in C_b^\infty(\mathbb{R}^n) but do not belong to L^2(\mathbb{R}^n). Therefore, the intersection C_b^\infty(\mathbb{R}^n) ∩ L^2(\mathbb{R}^n) is what is dense in L^2(\mathbb{R}^n).

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Let C_b^\infty(\mathbb{R}^n) be the space of infinitely differentiable functions f, such that f and all its partial derivatives are bounded.

Is C_b^\infty(\mathbb{R}^n) dense in L^2(\mathbb{R}^n)? I think the answer is yes, because C_b^\infty(\mathbb{R}^n) contains C_0^\infty(\mathbb{R}^n), the space of all infinitely differentiable functions with compact support, as a subset. And it's well known that C_0^\infty(\mathbb{R}^n) is dense in L^p(\mathbb{R}^n).

However, there appear to be functions in C_b^\infty(\mathbb{R}^n) but are not in L^2(\mathbb{R}^n), for example the function f(x)=1. So this means that instead, we have C_b^\infty(\mathbb{R}^n)\cap L^2(\mathbb{R}^n) dense in L^2(\mathbb{R}^n)?
 
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You seem to have answered your own question.
 

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