Density of a Compressed Sphere: Does Halving the Radius Double the Density?

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Homework Help Overview

The discussion revolves around the relationship between the radius of a sphere and the density of air contained within it, specifically exploring whether halving the radius results in a doubling of density. The subject area includes concepts of density, volume, and the properties of geometric shapes.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the effects of halving the radius on density, with some attempting to calculate the resulting density based on initial values. Questions arise regarding the factors involved in these calculations and the relationship between volume and density.

Discussion Status

Participants are actively engaging with the problem, with some offering calculations and others questioning the reasoning behind specific numerical factors. There is a mix of attempts to clarify concepts and explore mathematical relationships, but no consensus has been reached on the final interpretation of the results.

Contextual Notes

Some participants note the importance of understanding the volume change when the radius is halved, and there is mention of specific initial density values provided in the textbook question. The discussion includes corrections to mathematical expressions related to the volume of a sphere.

snubbly
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Air in a sphere has density "x" kg/m3

If radius is halved and air is compressed... does density double? ("2x" km/m3)
 
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One thing at a time. Suppose only one of these happened. Say the radius is halved. Does the density increase or decrease and by what factor? Once you figure that out, compress the air some more and see what happens to the final density relative to the initial.
 
Radius halved - density would increase.

I don't know by what factor though...

I have the Q&A ... initial is 1.4 kg/m3 and once radius is halved, density is 11 kg/m3.

I have to show working and I just can't figure it out.

Multiplying 1.4 by 7.9 gives me the answer, but I don't understand.
 
snubbly said:
Multiplying 1.4 by 7.9 gives me the answer, but I don't understand.
What's the magical 7.9? Or did you just do 11 kg/m3 / 1.4kg/m3
 
mg0stisha said:
What's the magical 7.9? Or did you just do 11 kg/m3 / 1.4kg/m3

yes, just the 11 / 1.4.

clueless.
 
What all are you given in the problem?
 
This is the question from the textbook:

Air enclosed in a sphere has density p = 1.4 kg/m3. What will the density be if the radius of the sphere is halved, compressing the air within?
 
What happens to the volume of a sphere if the radius is halved?
 
let say: D = Density
m = mass
v = volume

D1 = 1.4 kg/m3

mass is constant since the air will only be compressed.

D = m/v yielding m = Dv

Therefore, D1v1=D2v2

but v of sphere is (3*pi*r3)/4

and r2=r1/2

You can get it now.
 
Last edited:
  • #10
Minor correction: volume of a sphere is [tex]V = \frac{4\pi r^{3}}{3}[/tex]
 
  • #11
Sorry. I interchanged 3 and 4.
 
  • #12
got your back ;)
 
  • #13
Thanks.
 
  • #14
A intuitive way to think about this: Think about a cube. If you cut the side lengths in half, what happens to volume? Halve one dimension and volume halves. Halve the second and volume decreases by a factor of 4. Halve the third and volume goes down how many times?

The same thing happens to a sphere.
 
  • #15
ideasrule said:
A intuitive way to think about this: Think about a cube. If you cut the side lengths in half, what happens to volume? Halve one dimension and volume halves. Halve the second and volume decreases by a factor of 4. Halve the third and volume goes down how many times?

The same thing happens to a sphere.

8.

Thank you, that really helped!
 

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