Density of states from 3D to 2D

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SUMMARY

The discussion focuses on transitioning from a three-dimensional (3D) density of states calculation to a two-dimensional (2D) scenario using the infinite potential well model. The energy equation for the 3D case is defined as \(E=\frac{\hbar \pi^2}{2m}(\frac{n_x^2}{l_x}+\frac{n_y^2}{l_y}+\frac{n_z^2}{l_z})\). By making one dimension, specifically \(l_x\), extremely small, the only viable quantum number \(n_x\) becomes 0, effectively reducing the system to 2D. This approach highlights the significance of dimensionality in quantum systems.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly the infinite potential well model.
  • Familiarity with the concept of density of states in both 3D and 2D systems.
  • Knowledge of quantum numbers and their role in energy calculations.
  • Basic grasp of the implications of dimensionality on physical systems.
NEXT STEPS
  • Explore the derivation of density of states for 2D systems in quantum mechanics.
  • Study the effects of dimensionality on quantum confinement and energy levels.
  • Learn about the implications of the infinite potential well model in various dimensions.
  • Investigate advanced topics in quantum mechanics, such as the transition from 2D to 1D systems.
USEFUL FOR

Students and researchers in quantum mechanics, physicists studying condensed matter, and anyone interested in the implications of dimensionality on quantum systems.

Matej Kurtulik
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Hi,
I know how to calculate density of states for both cases, but it is not clearly to me how I can go from 3D case to 2D. I have energy from infinite potential well for 3D
$$E=\frac{\hbar \pi^2}{2m}(\frac{n_x^2}{l_x}+\frac{n_y^2}{l_y}+\frac{n_z^2}{l_z})$$
let make one dimension very small
$$l_x<<1$$
I should come to 2D conclusion, but I don't see any difference.

Thanks
 
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If ##l_x## is extremely small, then the only possible value of ##n_x## is 0, as the energy for excitation would be too big. The system is then reduced to 2D.
 
You could try making it very big instead.
 

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