Dependent theorem and bayes theorem.

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Homework Help Overview

The discussion revolves around a probability problem involving a box of 12 eggs, where the probabilities of all eggs being good, one being bad, and two being bad are provided. The central question is to determine the probability that all eggs are good given that two randomly selected eggs are good, utilizing Bayes' theorem.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to apply Bayes' theorem to find the desired probability. There is a focus on understanding the dependencies between events, particularly how to calculate the probability of selecting two good eggs given different scenarios of good and bad eggs.

Discussion Status

Some participants are actively exploring the calculations needed to find the probability of selecting two good eggs. There is mention of needing to compute probabilities for different configurations of good and bad eggs, indicating a productive exploration of the problem. However, no consensus or resolution has been reached yet.

Contextual Notes

Participants are grappling with the implications of dependent events in their calculations and are seeking clarification on how to approach the problem given the probabilities provided. There is an emphasis on the need for additional computations to progress in the discussion.

iTee
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Homework Statement



One box of eggs has 12 eggs. The probability of all eggs being good is 70%. The probability of one being bad is 20%. The probability of two being bad is 10%. Given that 2 randomly selected eggs are good, what is the probability that all the eggs will be good?

Homework Equations





The Attempt at a Solution



According to bayes theorem,

P(all good | random 2 are good) = ( P(random 2 are good | all good) * P(all good) ) / P(random two are good)


Now, P(random 2 are good | all good) = P(random 2 are good <and> all good) / P(all good)

=> " P(random 2 are good <and> all good) " are dependent events. Can't seem to figure out how to get around this.
 
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iTee said:

Homework Statement



One box of eggs has 12 eggs. The probability of all eggs being good is 70%. The probability of one being bad is 20%. The probability of two being bad is 10%. Given that 2 randomly selected eggs are good, what is the probability that all the eggs will be good?

Homework Equations





The Attempt at a Solution



According to bayes theorem,

P(all good | random 2 are good) = ( P(random 2 are good | all good) * P(all good) ) / P(random two are good)


Now, P(random 2 are good | all good) = P(random 2 are good <and> all good) / P(all good)

=> " P(random 2 are good <and> all good) " are dependent events. Can't seem to figure out how to get around this.

For b = 0,1,2, what are P(random 2 are good|12-b good and b bad)? So, what is P(random 2 are good)?

RGV
 
I am currently working on a very very similar question on my own. But, the problem I have is finding the P(Random 2 are good).

Needed Information
P(all are good) = 0.7
P(Random 2 are good | all are good) = 1 (since given all are good, any random ones will be guranteed to be good)
P(Random 2 are good) This is where I struggle, how to find this?
 
lovemake1 said:
I am currently working on a very very similar question on my own. But, the problem I have is finding the P(Random 2 are good).

Needed Information
P(all are good) = 0.7
P(Random 2 are good | all are good) = 1 (since given all are good, any random ones will be guranteed to be good)
P(Random 2 are good) This is where I struggle, how to find this?

Read the question immediately above this one. Have you done the two other computations? Until you do that, you will be unable to get anywhere. I will just give one more hint: what is P(both good|1 bad, 19 good in carton)? Well, you are GIVEN that the carton has 19 good eggs in it, and one bad egg. You draw 2 eggs at random, and want the probability that both are good. Surely you must have seen or done such problems before, but if not: (i) what is the probability the first drawn egg is good? (ii) given that the first egg is good, we now are left with 19 eggs (18 good, one bad), so now what is the probability of drawing another good egg?

RGV
 

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