1. The problem statement, all variables and given/known data A 1.6 m long glass tube closed at one end is weighted and lowered to the bottom of a freshwater lake. When the tube is recovered, an indicator mark shows that water rose to within 0.32 m of the closed end. Assume the temperature is constant, the acceleration of gravity is 9.8 m/s2, the density of the glass is 3400 kg/m3 , the density of the lake water is 1000 kg/m3, and air pressure is 1.013 × 105 Pa. Determine the depth of the lake. Answer in units of m. 2. Relevant equations P = PA + PLake Plake = rho * g * h (h = depth of lake) rho = m / V V = pi * r2 * L1 (L1 = 1.6 m) 3. The attempt at a solution So I tried setting up a proportion: L1 / L2 (L2 = 0.32 m ) = PA / PL (L2PA) / L2 = PL = rho * g * h From there, h seems to be easy to figure out, but I don't think my process is right because I ignored the density of the glass given. Can someone help me?