Derivation of 2nd divided difference

  • Context: Undergrad 
  • Thread starter Thread starter roldy
  • Start date Start date
  • Tags Tags
    Derivation Difference
Click For Summary

Discussion Overview

The discussion revolves around the formulation of the second divided difference in the context of mathematical analysis. Participants explore the relationship between first and second divided differences, particularly focusing on the use of induction in deriving the second divided difference from the first. The conversation includes technical reasoning and attempts to clarify the underlying concepts.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant seeks clarification on how the second divided difference is derived from the first, specifically questioning the role of induction in this process.
  • Another participant provides a link to an external resource that may contain relevant information regarding the topic.
  • A different participant attempts to express the formulation of the second divided difference using the first differences, although the notation appears incomplete.
  • One participant acknowledges the use of substitution in the derivation process but admits to struggling with the application of first differences to first differences.

Areas of Agreement / Disagreement

The discussion does not reach a consensus on the derivation process, as participants express varying levels of understanding and approach to the topic. Multiple viewpoints and methods are presented without resolution.

Contextual Notes

Some mathematical expressions and notations are incomplete or unclear, which may affect the clarity of the arguments presented. The discussion relies on the assumption that participants have a foundational understanding of divided differences.

roldy
Messages
206
Reaction score
2
I'm trying to understand how the second divided difference is formulated. I understand that the first divided difference is just the equation of a slope.

[itex]f(x_{i},x_{i+1})=\frac{f(x_{i})-f(x_{i+1})}{x_{i}-x_{i+1}}[/itex]

Every source that I have read always jumps to the second divided difference by saying "and by induction"

[itex]f(x_{i},x_{i+1},x_{i+2})=\frac{f(x_{i},x_{i+1})-f(x_{i+1},x_{i+2})}{x_{i+2}-x_{i+1}}[/itex]

How is induction used to get this equation?
 
Physics news on Phys.org
http://nptel.iitm.ac.in/courses/Webcourse-contents/IIT-KANPUR/mathematics-2/node112.html

you can check the above site if you think it would be useful.
 
Last edited by a moderator:
Having got two consecutive first differences,
[tex]\frac{f(x_i)- f(x_{i+1}}{x_i- x_{i+1}}[/tex]
[tex]\frac{f(x_{i+1}- f(x_{i+2}}{x_{i+1}- x_{i+2}}[/tex]

Now, for the first difference of those:
[tex]\frac{\frac{f(x_i)- f(x_{i+1}}{x_i- x_{i+1}}- \frac{f(x_{i+1}- f(x_{i+2}}{x_{i+1}- x_{i+2}}}{x_i- x_{i+2}}[/tex]
 
Thank you. I new it was some type of substitution but I failed to think of using the first difference with the first differences.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
Replies
6
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
8
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K