Graduate Derivation of the Casimir energy in flat space

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The discussion focuses on the derivation of the Casimir energy, particularly the role of large plate dimensions in integrating over k-space dimensions. It highlights that the vacuum energy is calculated by summing over excitation modes, and large plate areas allow for integration in two dimensions of k-space due to periodic boundary conditions. The approximation of a sum by an integral is valid when the plate dimensions are significantly larger than their separation, minimizing edge effects. This leads to quantized momenta and simplifies calculations for momentum components parallel to the plates, while the perpendicular component remains distinct. Understanding these relationships is crucial for accurately deriving the Casimir effect in flat space.
highflyyer
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I am trying to understand the derivation of the Casimir energy from https://en.wikipedia.org/wiki/Casim...f_Casimir_effect_assuming_zeta-regularization.

At one point, the derivation writes the following:

The vacuum energy is then the sum over all possible excitation modes ##\omega_{n}##. Since the area of the plates is large, we may sum by integrating over two of the dimensions in ##k##-space. The assumption of periodic boundary conditions yields
$$\langle E \rangle=\frac{\hbar}{2} \cdot 2 \int \frac{A dk_x dk_y}{(2\pi)^2} \sum_{n=1}^\infty \omega_n$$


What does the size of the plates have to do with being able to integrate over two of the dimensions in ##k##-space? I don't quite see the connection.

Thank you so much in advance for any comments.
 
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For example they don't need to care for diffraction. And they don't care about what is happening around corners since that part is very small when you have large plate.
 
If you have periodic boundary conditions in a cuboid volume, the momenta are quantized: ##p_j=\frac{2 \pi}{L_j} n## with ##n \in \mathbb{Z}##. For large ##L_j## you can often approximate a sum over ##p_j## by an integral
$$\sum_{p_j} \rightarrow \frac{L}{2 \pi \hbar} \int_{\mathbb{R}} \mathrm{d}p_j.$$
Here you assume that the plates are very large compared to their distance. Thus you can use the approximation of the sum by an integral for the momentum components along the plates but not for the one perpendicular to it.
 
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Thank you.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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