Derivation of the Casimir energy in flat space

Click For Summary

Discussion Overview

The discussion revolves around the derivation of the Casimir energy in flat space, specifically focusing on the mathematical treatment of the vacuum energy and the implications of the size of the plates involved in the Casimir effect. The scope includes theoretical aspects and mathematical reasoning related to quantum field theory.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions the connection between the size of the plates and the ability to integrate over two dimensions in k-space, seeking clarification on this aspect.
  • Another participant suggests that large plates eliminate concerns about diffraction and effects around corners, implying that these factors become negligible.
  • A different participant explains that with periodic boundary conditions in a cuboid volume, momenta are quantized, and for large dimensions, a sum over momentum can be approximated by an integral, specifically for the momentum components along the plates, while noting that this does not apply to the perpendicular direction.

Areas of Agreement / Disagreement

Participants express differing levels of understanding regarding the implications of plate size on the derivation, with some providing clarifications while others remain uncertain about the initial question posed.

Contextual Notes

The discussion does not resolve the initial query about the connection between plate size and integration in k-space, leaving some assumptions and dependencies on definitions unaddressed.

highflyyer
Messages
27
Reaction score
1
I am trying to understand the derivation of the Casimir energy from https://en.wikipedia.org/wiki/Casim...f_Casimir_effect_assuming_zeta-regularization.

At one point, the derivation writes the following:

The vacuum energy is then the sum over all possible excitation modes ##\omega_{n}##. Since the area of the plates is large, we may sum by integrating over two of the dimensions in ##k##-space. The assumption of periodic boundary conditions yields
$$\langle E \rangle=\frac{\hbar}{2} \cdot 2 \int \frac{A dk_x dk_y}{(2\pi)^2} \sum_{n=1}^\infty \omega_n$$


What does the size of the plates have to do with being able to integrate over two of the dimensions in ##k##-space? I don't quite see the connection.

Thank you so much in advance for any comments.
 
Physics news on Phys.org
For example they don't need to care for diffraction. And they don't care about what is happening around corners since that part is very small when you have large plate.
 
If you have periodic boundary conditions in a cuboid volume, the momenta are quantized: ##p_j=\frac{2 \pi}{L_j} n## with ##n \in \mathbb{Z}##. For large ##L_j## you can often approximate a sum over ##p_j## by an integral
$$\sum_{p_j} \rightarrow \frac{L}{2 \pi \hbar} \int_{\mathbb{R}} \mathrm{d}p_j.$$
Here you assume that the plates are very large compared to their distance. Thus you can use the approximation of the sum by an integral for the momentum components along the plates but not for the one perpendicular to it.
 
  • Like
Likes   Reactions: highflyyer and Demystifier
Thank you.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K