Derivation of the Equilibrium Constant

  • Thread starter gsingh2011
  • Start date
  • #1
gsingh2011
115
1
I'm trying to understand this: http://en.wikipedia.org/wiki/Equilibrium_constant#Derivation_from_Gibbs_Free_Energy
And there are few steps that I don't get. My first question is probably a stupid one, but where does the [tex]\Sigma[/tex]v[tex]_{j}[/tex]A[tex]_{j}[/tex]=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n?

I'll ask my other questions after I get some replies because it's possible I'll figure them out after I read the replies.
 

Answers and Replies

  • #2
Borek
Mentor
29,138
3,771
where does the [tex]\Sigma[/tex]v[tex]_{j}[/tex]A[tex]_{j}[/tex]=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n?

My guess is it is just a mass conservation, and yes, products are negative.
 
  • #3
gsingh2011
115
1
My guess is it is just a mass conservation, and yes, products are negative.

Ok, but why does it only sum up to n? The first equation in the derivation shows the first product being n but then shows more products after that. If it was mass conservation, wouldn't it have to sum passed n?
 
  • #4
Borek
Mentor
29,138
3,771
Where does it sum only to n? It sums for all j.
 

Suggested for: Derivation of the Equilibrium Constant

Replies
6
Views
586
  • Last Post
Replies
3
Views
163
  • Last Post
Replies
1
Views
410
  • Last Post
Replies
5
Views
552
Replies
3
Views
687
  • Last Post
Replies
2
Views
630
Replies
8
Views
3K
Top