Derivation process of Selection Rule of hydrogenic atom

Click For Summary
SUMMARY

The discussion centers on the derivation process of the selection rule for hydrogenic atoms, specifically addressing the quantum number n's lack of regulation in selection rules. Participants explore the integral of the radial part, represented as ∫∞0[rRnl(r)]Rn′l′(r)r2dr, noting that it remains non-zero when n differs from n'. The integral's evaluation involves the orthogonality of wavefunctions, particularly when considering associated Laguerre polynomials and their implications on quantum states with different n but identical l and m quantum numbers.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of hydrogenic atom wavefunctions
  • Knowledge of associated Laguerre polynomials
  • Familiarity with the orthogonality principle in quantum mechanics
NEXT STEPS
  • Study the properties of associated Laguerre polynomials in quantum mechanics
  • Research the orthogonality of quantum states and its implications
  • Explore the derivation of selection rules for hydrogenic atoms
  • Learn about the evaluation of integrals involving spherical harmonics
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on atomic physics and selection rules in hydrogenic systems.

smjchris
Messages
1
Reaction score
0
Homework Statement
Prove that the radial integral is always non-zero
Relevant Equations
Selection rule, wavefunction of hydrogeninc atom.
This page is Quantum mechanics by bransden. My homework is explain why there is no regulation of quantum number n in selection rule. Also explain that by solving that integral of radial part is always non-zero.

∫∞0[rRnl(r)]Rn′l′(r)r2dr

(n is different with n')

I tried to solve it by just calculate it, but I can't calculate the associated laguerre polynomial. I think the answer is using orthogonality, but how can I solve it?

pdfcoffee.com_quantum-mechanics-bransden-pdf-2-pdf-free.png
 
Last edited by a moderator:
Physics news on Phys.org
smjchris said:
Also explain that by solving that integral of radial part is always non-zero.
I think always is too strong. Consider two wavefunctions with different ##n## but the same ##l## and ##m## quantum numbers. What should the following integral give you?$$I=\int_0^{\infty}R_{n'l}R_{nl}~r^2dr\int_0^{2\pi}d\phi\int_0^{\pi}Y^*_{lm}Y_{lm}~\sin\theta d\theta.$$
 
  • Like
Likes   Reactions: PeroK

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K